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The_Cambridge_Handbook_of_Physics_Formulas

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2.12 Laplace transforms<br />

55<br />

2.12 Laplace transforms<br />

Laplace transform theorems<br />

Definition a F(s)=L{f(t)} =<br />

Convolution b<br />

∫ ∞<br />

0<br />

f(t)e −st dt (2.514)<br />

{∫ ∞<br />

}<br />

F(s)·G(s)=L f(t−z)g(z)dz (2.515)<br />

0<br />

= L{f(t)∗g(t)} (2.516)<br />

L{}<br />

F(s)<br />

G(s)<br />

∗<br />

Laplace<br />

transform<br />

L{f(t)}<br />

L{g(t)}<br />

convolution<br />

2<br />

Inverse c f(t)= 1<br />

2πi<br />

∫ γ+i∞<br />

γ−i∞<br />

e st F(s)ds (2.517)<br />

= ∑ residues (for t>0) (2.518)<br />

γ<br />

constant<br />

Transform <strong>of</strong><br />

derivative<br />

Derivative <strong>of</strong><br />

transform<br />

{ d n }<br />

f(t)<br />

L<br />

dt n<br />

∑n−1<br />

= s n L{f(t)}−<br />

r=0<br />

s n−r−1 dr f(t)<br />

∣<br />

∣∣t=0<br />

dt r<br />

(2.519)<br />

d n F(s)<br />

ds n = L{(−t) n f(t)} (2.520)<br />

n integer > 0<br />

Substitution F(s−a)=L{e at f(t)} (2.521) a constant<br />

Translation<br />

e −as F(s)=L{u(t−a)f(t−a)} (2.522)<br />

{<br />

0 (t0)<br />

u(t)<br />

unit step<br />

function<br />

a If |e −s 0t f(t)| is finite for sufficiently large t, the Laplace transform exists for s>s 0 .<br />

b Also known as the “faltung (or folding) theorem.”<br />

c Also known as the “Bromwich integral.” γ is chosen so that the singularities in F(s) are left <strong>of</strong> the integral line.

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