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December 01, 2011 - vlambaram

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www.<strong>vlambaram</strong>.com<br />

Answers<br />

S.F. Xavier (ASRy›)<br />

(1) -72= a x 3 x 2 x 1 =6a a = -72/6 = -12<br />

Leading coefficient - 12<br />

VLAMBARAM TM<br />

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(2) f(x) = a(x - 4) 2 (x + 2) (2x - 3) 24 = a (0 - 4) 2 (0 + 2) 2 (2 x 0 - 3)<br />

24 = a (16) (2) (-3) a = 24/16 x 2 - 3<br />

= - 0.25 f(x) = -1/4 (x - 4) 2 (x + 2) 2 (2x - 3)<br />

(3) f(x) = 3x4 - 2x2 + 1 f(-x) = 3(-x) 4 - 2(-x) 2<br />

=3x2 - 2x2 + 1<br />

f(-x) = f(x) Thus the function is an even function.<br />

Therefore there is a symmetry at x = 0<br />

(4) dx/dt = 15km/h<br />

dy/dt = 20 km/h<br />

Find dr/dt when r = 2h<br />

r2 = x2 + y2 - 2xy π/3<br />

=x2 + y2 - 2xy (1/2)<br />

=x2 + y2 - xy<br />

2r dr/dt = 2x dx/dt + 2y dy/dt - (dx/dt y + dy/dt x)<br />

At t = 2h, x = 30, y = 40 and r2 = 302 + 402 - 2 (30) (40) π/3<br />

= 2500 - 2 (1200) (1/2) =1300<br />

r = 10√13 r > 0 2 (10√13 dr/dt = 900 + 1600 - (600 + 600)<br />

MATH, SCIENCE & ENGLISH TUITION<br />

Math & Physics taken for all grades from grade 4 to 1 st year<br />

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BY. Mr. S.F. Xavier (Teacher) -TEL: 647.340.9490 / 647.831.0070<br />

=1300 dr/dt = 130/a√13 = 5 √13<br />

The distance between the cyclist in incrasing at a rats of 5√13km / h after 2 hours.<br />

(5) 24/26 . 1/26. 1/26 = 24/26 3 = 3/2197<br />

First is 24/26 because the last two letter y z is out<br />

Tutorial 290 Questions<br />

(1) In a lottery called “6 is a raw” six different numbers are chosen at random from<br />

1 through 49 inclusive. If a ticket has been purchased find the probability the grand<br />

prize in won where all six numbers match? (For Gr. 12)<br />

(2) Let f(x) = x + 4 and g(x) = (x - 2) 2 . Find a function u so that<br />

f (g (u(x) = 4x2 - 8x + 8.<br />

(3) If f(x) = 2x - 7, and g(x) = 5 - 2x show that (f o g) - 1 = g -1 o f -1<br />

(4) Find the equation of the normal at (2, 3) to the curve<br />

x3 + y3 - 3xy = 17 at point (2, 3)<br />

(5) An object moves so that its velocity, V is related to its position, s, according to<br />

V = √b2 + 2gs, where b and g are anstants. Show that the acceleration of<br />

the object is constant. (For Gr. 12)<br />

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www.<strong>vlambaram</strong>.com<br />

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