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General Chemistry Principles, Patterns, and Applications, 2011

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A more complex example of this type of problem is the conversion of n-butane, an additive used to<br />

increase the volatility of gasoline, to isobutane (2-methylpropane). This reaction can be written as follows:<br />

Equation 15.26<br />

n - butane g<br />

( ) isobutane( g)<br />

<strong>and</strong> the equilibrium constant K = [isobutane]/[n-butane]. At equilibrium, a mixture ofn-butane <strong>and</strong><br />

isobutane at room temperature was found to contain 0.041 M isobutane <strong>and</strong> 0.016 M n-butane.<br />

Substituting these concentrations into the equilibrium constant expression,<br />

Equation 15.27<br />

K = [ isobutane][n - butane] = 0.041 M0.016 M = 2.6<br />

Thus the equilibrium constant for the reaction as written is 2.6.<br />

E X A M P L E 8<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

1372

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