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General Chemistry Principles, Patterns, and Applications, 2011

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oxidized to H + <strong>and</strong> O 2 will be reduced to O 2− , but what are the actual products? A reasonable<br />

guess is B 2O 3 <strong>and</strong> H 2O, both stable compounds.<br />

b. Neither BCl 3 nor water is a powerful oxidant or reductant, so a redox reaction is unlikely;<br />

a hydrolysis reaction is more probable. Nonmetal halides are acidic <strong>and</strong> react with water<br />

to form a solution of the hydrohalic acid <strong>and</strong> a nonmetal oxide or hydroxide. In this case,<br />

the most probable boron-containing product is boric acid [B(OH) 3].<br />

c. We normally expect a boron trihalide to behave like a Lewis acid. In this case, however,<br />

the other reactant is elemental hydrogen, which usually acts as a reductant. The iodine<br />

atoms in BI 3 are in the lowest accessible oxidation state (−1), <strong>and</strong> boron is in the +3<br />

oxidation state. Consequently, we can write a redox reaction in which hydrogen is<br />

oxidized <strong>and</strong> boron is reduced. Because compounds of boron in lower oxidation states<br />

are rare, we expect that boron will be reduced to elemental boron. The other product of<br />

the reaction must therefore be HI.<br />

Exercise<br />

Predict the products of the reactions <strong>and</strong> write a balanced chemical equation for each reaction.<br />

a. B 2<br />

H 6<br />

g<br />

a. BBr 3(l) + O 2(g) →<br />

a. B 2<br />

O 3<br />

s<br />

( ) + H 2<br />

O( l) - ® D<br />

( ) + Ca( s) - ® D<br />

( ) + H 2<br />

O( l) - ® D 2B( OH ) 3<br />

( s) + 6H 2 ( g)<br />

Answer: a. B 2<br />

H 6<br />

g<br />

BBr 3(l) + O 2(g) → no reaction a. b. 6B 2<br />

O 3 ( s) + 18Ca s<br />

( ) - ® D B 12 ( s) + 18CaO ( s)<br />

a. Reactions <strong>and</strong> Compounds of the Heavier Group 13 Elements<br />

All four of the heavier group 13 elements (Al, Ga, In, <strong>and</strong> Tl) react readily with the halogens to form<br />

compounds with a 1:3 stoichiometry:<br />

Equation 22.10<br />

2M(s) + 3X 2 (s,l,g) → 2MX 3 (s) or M 2 X 6<br />

The reaction of Tl with iodine is an exception: although the product has the stoichiometry TlI3, it<br />

is not thallium(III) iodide, but rather a thallium(I) compound, the Tl + salt of the triiodide ion (I3 − ). This<br />

compound forms because iodine is not a powerful enough oxidant to oxidize thallium to the +3 oxidation<br />

state.<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

1992

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