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General Chemistry Principles, Patterns, and Applications, 2011

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1. Beryllium iodide reacts vigorously with water to produce HI. Write a balanced chemical equation for this<br />

reaction <strong>and</strong> explain why it is violent.<br />

2. Predict the products of each reaction <strong>and</strong> then balance each chemical equation.<br />

a. Mg(OH) 2 (aq) + (NH 4 ) 3 PO 4 (aq) →<br />

b. calcium carbonate <strong>and</strong> sulfuric acid →<br />

c. CaCl 2 (aq) + Na 3 PO 4 (aq) →<br />

d. the thermal decomposition of SrCO 3<br />

3. Predict the products of each reaction <strong>and</strong> then balance each chemical equation.<br />

a. Sr(s) + O 2 (g) →<br />

b. the thermal decomposition of CaCO 3 (s)<br />

c. CaC 2 (s) + H 2 O(l) →<br />

d. RbHCO 3 (s) + H 2 SO 4 (aq) →<br />

4. Indicate whether each pair of substances will react <strong>and</strong>, if so, write a balanced chemical equation for the<br />

reaction.<br />

a. an alkyl chloride <strong>and</strong> magnesium metal<br />

b. strontium metal <strong>and</strong> nitrogen<br />

c. magnesium metal <strong>and</strong> cold water<br />

d. beryllium <strong>and</strong> nitrogen<br />

5. Using a thermodynamic cycle <strong>and</strong> information presented in Chapter 7 "The Periodic Table <strong>and</strong> Periodic<br />

Trends" <strong>and</strong> Chapter 8 "Ionic versus Covalent Bonding", calculate the lattice energy of<br />

magnesium nitride ( Mg 3<br />

N 2 ). (DH f for Mg 3<br />

N 2<br />

is - 463 kJ / mol, <strong>and</strong> DH° for<br />

6. N(g) + 3e − → N 3− is +1736 kJ.) How does the lattice energy of Mg 3 N 2 compare with that of MgCl 2 <strong>and</strong> MgO?<br />

(See Chapter 25 "Appendix A: St<strong>and</strong>ard Thermodynamic Quantities for Chemical Substances at 25°C" for the<br />

enthalpy of formation values.)<br />

7. The solubility products of the carbonate salts of magnesium, calcium, <strong>and</strong> strontium are 6.82 × 10 −6 , 3.36 ×<br />

10 −9 , <strong>and</strong> 5.60 × 10 −10 , respectively. How many milligrams of each compound would be present in 200.0 mL of<br />

a saturated solution of each? How would the solubility depend on the pH of the solution? Why?<br />

8. The solubility products of BaSO 4 <strong>and</strong> CaSO 4 are 1.08 × 10 −10 <strong>and</strong> 4.93 × 10 −5 , respectively. What accounts for<br />

this difference? When 500.0 mL of a solution that contains 1.00 M Ba(NO 3 ) 2 <strong>and</strong> 3.00 M Ca(NO 3 ) 2 is mixed<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

1968

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