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General Chemistry Principles, Patterns, and Applications, 2011

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Answer:<br />

a. Ag + (aq); H 2O 2(aq)<br />

b. H 2O 2(aq)<br />

E X A M P L E 6<br />

Use the data in Table 19.2 "St<strong>and</strong>ard Potentials for Selected Reduction Half-Reactions at 25°C" to determine<br />

whether each reaction is likely to occur spontaneously under st<strong>and</strong>ard conditions:<br />

a. Sn(s) + Be 2+ (aq) → Sn 2+ (aq) + Be(s)<br />

a. MnO 2(s) + H 2O 2(aq) + 2H + (aq) → O 2(g) + Mn 2+ (aq) + 2H 2O(l)<br />

Given: redox reaction <strong>and</strong> list of st<strong>and</strong>ard electrode potentials (Table 19.2 "St<strong>and</strong>ard Potentials for Selected<br />

Reduction Half-Reactions at 25°C")<br />

Asked for: reaction spontaneity<br />

Strategy:<br />

A Identify the half-reactions in each equation. Using Table 19.2 "St<strong>and</strong>ard Potentials for Selected Reduction<br />

Half-Reactions at 25°C", determine the st<strong>and</strong>ard potentials for the half-reactions in the appropriate direction.<br />

B Use Equation 19.10 to calculate the st<strong>and</strong>ard cell potential for the overall reaction. From this value,<br />

determine whether the overall reaction is spontaneous.<br />

Solution:<br />

a. A Metallic tin is oxidized to Sn 2+ (aq), <strong>and</strong> Be 2+ (aq) is reduced to elemental beryllium. We can find<br />

the st<strong>and</strong>ard electrode potentials for the latter (reduction) half-reaction (−1.85 V) <strong>and</strong> for the former<br />

(oxidation) half-reaction (−0.14 V) directly from Table 19.2 "St<strong>and</strong>ard Potentials for Selected Reduction<br />

Half-Reactions at 25°C".<br />

B Adding the two half-reactions gives the overall reaction:<br />

( ) + 4H + ( aq) + 2e -<br />

( ) + 2H 2O( l) H 2O2( aq) ® O2( g) + 2H + ( aq)<br />

( ) + H 2O2( aq) + 2H + ( aq) ® O2(g) + Mn2<br />

( ) + 2H 2O l<br />

cathode :anode :overall : MnO2 s<br />

® Mn2 + aq<br />

+2e - MnO2 s<br />

+ aq ( )E°cathode = 1.22 VE°anode = 0.70 VE°cell<br />

= E°cathode - E°anode = -0.53 V<br />

The st<strong>and</strong>ard cell potential is quite negative, so the reaction will notoccur spontaneously as written. That<br />

is, metallic tin cannot be used to reduce Be 2+ to beryllium metal under st<strong>and</strong>ard conditions. Instead, the<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

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