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General Chemistry Principles, Patterns, and Applications, 2011

General Chemistry Principles, Patterns, and Applications, 2011

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a. Sodium hydroxide is an ionic compound that is a strong electrolyte (<strong>and</strong> a strong base)<br />

in aqueous solution:<br />

NaOH(s) → H 2 O(l) Na + (aq) + OH – (aq)<br />

B Because each formula unit of NaOH produces one Na + ion <strong>and</strong> one OH − ion, the concentration of<br />

each ion is the same as the concentration of NaOH: [Na + ] = 0.21 M <strong>and</strong> [OH − ] = 0.21 M.<br />

b. A The formula (CH 3) 2CHOH represents 2-propanol (isopropyl alcohol) <strong>and</strong> contains the –<br />

OH group, so it is an alcohol. Recall from Section 4.1 "Aqueous Solutions" that alcohols are<br />

covalent compounds that dissolve in water to give solutions of neutral molecules. Thus alcohols<br />

are nonelectrolytes.<br />

B The only solute species in solution is therefore (CH 3) 2CHOH molecules, so [(CH 3) 2CHOH] = 3.7 M.<br />

c. A Indium nitrate is an ionic compound that contains In 3+ ions <strong>and</strong> NO 3− ions, so we expect<br />

it to behave like a strong electrolyte in aqueous solution:<br />

In(NO 3 ) 3 (s) → H 2 O(l) In 3+ (aq) + 3NO 3 – (aq)<br />

B One formula unit of In(NO 3) 3 produces one In 3+ ion <strong>and</strong> three NO 3− ions, so a 0.032 M<br />

In(NO 3) 3 solution contains 0.032 M In 3+ <strong>and</strong> 3 × 0.032 M = 0.096 M NO 3– —that is, [In 3+ ] = 0.032 M<br />

<strong>and</strong> [NO 3− ] = 0.096 M.<br />

Exercise<br />

What are the concentrations of all species derived from the solutes in these aqueous solutions?<br />

a. 0.0012 M Ba(OH) 2<br />

b. 0.17 M Na 2SO 4<br />

c. 0.50 M (CH 3) 2CO, commonly known as acetone<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

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