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General Chemistry Principles, Patterns, and Applications, 2011

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1.<br />

a. Give the hybridization of all atoms except hydrogen in this pheromone.<br />

b. How many σ bonds are present in this molecule? How many π bonds are there?<br />

c. Describe the bonding in this molecule using a combination of the localized <strong>and</strong> delocalized<br />

approaches.<br />

2. Carbon monoxide is highly poisonous because it binds more strongly than O 2 to the iron in red blood cells,<br />

which transport oxygen in the blood. Consequently, a victim of CO poisoning suffocates from a lack of<br />

oxygen. Draw a molecular orbital energy-level diagram for CO. What is the highest occupied molecular<br />

orbital? Are any of the molecular orbitals degenerate? If so, which ones?<br />

A N S W E R<br />

1.<br />

a. a. There are six electron groups, the molecular geometry is octahedral, <strong>and</strong> the hybridization of S is sp 3 d 2 .<br />

b. With six fluorine atoms packed around the central sulfur atom, there is no room for another<br />

species to approach the sulfur to initiate a reaction. The polar S–F bonds are also expected to<br />

be quite strong, so breaking an S–F bond to initiate a reaction is unlikely under most conditions.<br />

c. SF 6 is a gas at room temperature because it has no net dipole moment; the individual S–F bond<br />

dipoles cancel one another in this highly symmetrical structure. The absence of a dipole<br />

moment results in very weak interactions between SF 6 molecules, <strong>and</strong> as a result SF 6 is a gas<br />

rather than a liquid or a solid at room temperature.<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

873

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