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General Chemistry Principles, Patterns, and Applications, 2011

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C Equate the ratios of those terms that change for the two sets of conditions. Making sure to use the<br />

appropriate units, insert the quantities <strong>and</strong> solve for the unknown parameter.<br />

Solution:<br />

A To see exactly which parameters have changed <strong>and</strong> which are constant, prepare a table of the initial <strong>and</strong><br />

final conditions:<br />

August (initial)<br />

T 30°C = 303 K<br />

P 0.980 atm<br />

January (final)<br />

−10°C = 263 K<br />

0.980 atm<br />

n 1.23 × 10 3 mol H2 1.23 × 10 3 mol H2<br />

V 31,150 L ?<br />

Thus we are asked to calculate the effect of a change in temperature on the volume of a fixed amount of<br />

gas at constant pressure.<br />

B Recall that we can rearrange the ideal gas law to give<br />

V = (nRP)(T )<br />

Both n <strong>and</strong> P are the same in both cases, which means that nR/P is a constant. Dividing both sides<br />

by T gives<br />

VT = nRP = constant<br />

This is the relationship first noted by Charles.<br />

C We see from this expression that under conditions where the amount (n) of gas <strong>and</strong> the pressure (P) do<br />

not change, the ratio V/T also does not change. If we have two sets of conditions for the same amount of<br />

gas at the same pressure, we can therefore write<br />

V1T1= V2T 2<br />

where the subscripts 1 <strong>and</strong> 2 refer to the initial <strong>and</strong> final conditions, respectively. Solving for V 2 <strong>and</strong><br />

inserting the given quantities in the appropriate units, we obtain<br />

V 2 = V1T 2T1<br />

= (31,350 L)(263 K)303 K<br />

= 2.70 ´104 L<br />

It is important to check your answer to be sure that it makes sense, just in case you have accidentally<br />

inverted a quantity or multiplied rather than divided. In this case, the temperature of the gas decreases.<br />

Saylor URL: http://www.saylor.org/books<br />

Saylor.org<br />

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