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n - PATh :.: Process and Product Applied Thermodynamics research ...

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Experimental Methods, Results <strong>and</strong> Discussion<br />

Table II.12: Solubility of Oxygen in n-Heptane. Comparison Between Data Measured in This<br />

Work <strong>and</strong> Literature Data.<br />

L2,1(T,p) (%)<br />

T ( K) This work<br />

Hesse et al.<br />

(1996)<br />

Makranczy et al.<br />

(1976)<br />

Gjaldbaek et al.<br />

(1963)<br />

298.15 0.335 ± 1 0.338 ± 0.5 0.322 ± 3 0.330 ± 1<br />

Figures II.11 <strong>and</strong> II.12 intend to emphasize the temperature dependence of the<br />

different systems studied. The influence of the chain length <strong>and</strong> structure of the molecule,<br />

as shape <strong>and</strong> partial substitution of fluorine atoms, was studied .<br />

The solute mole fraction is usually presented at a solute’s partial pressure equal to<br />

1 atm. From solute’s mole fraction data reported in Table II.13, it is simple to calculate the<br />

corrected solute mole fraction since the Henry’s law is applicable at the working<br />

conditions. In order to check the validity of the Henry’s law for the systems under study,<br />

the solubility of oxygen in perfluoro-n-nonane was measured at several pressures different<br />

from atmospheric <strong>and</strong> at a fixed temperature of 298 K. Solubility data measured is given in<br />

Figure II.13. The linear relation obtained confirms the validity of the Henry’s law for these<br />

systems.<br />

The temperature dependence of the experimental values of the solubilities<br />

expressed in mole fraction x2 (T, P), where P is equal to 1 atm was correlated using the<br />

following equation suggested by Benson <strong>and</strong> Krause (1976)<br />

1<br />

−i<br />

ln x2<br />

= ∑ AiT<br />

(II.18)<br />

i=<br />

0<br />

The values obtained for the coefficients Ai for the different systems are given in<br />

Table II.14, together with the AAD of the experimental results defined as<br />

AAD = N<br />

N<br />

−1<br />

∑<br />

i=<br />

1<br />

δ (II.19)<br />

i<br />

where N is the number of data points, whose individual percentage deviations are<br />

calculated as:<br />

[ x ( exp)<br />

x ( calc)<br />

] / x ( calc)<br />

δ = 100 −<br />

(II.20)<br />

i 2<br />

2<br />

2<br />

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