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Tema 3: Resolución de sistemas mediante determinantes

Tema 3: Resolución de sistemas mediante determinantes

Tema 3: Resolución de sistemas mediante determinantes

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°§¢§£UNIDAD32 1 0 –1)5 1 –3 –7D =7 2 –3 –8(1 0 2 22 1Tomamos un menor <strong>de</strong> or<strong>de</strong>n 2 distinto <strong>de</strong> cero: | = –3 ? 0. Luego las dos primerasfilas son linealmente in<strong>de</strong>pendientes.5 1 ||2 1 0|Como 5 1 –3 = –9 ? 0, la 1. a , 2. a y 4. a fila son linealmente in<strong>de</strong>pendientes.1 0 2La 3. a fila es la suma <strong>de</strong> las dos primeras. Luego ran (D) = 3.Página 821. Averigua si los siguientes <strong>sistemas</strong> son compatibles o incompatibles:° 3x – 2y = 5§a) ¢ x + 3y = –2b)§£ 2x – y = 3°§¢§£4x + 5y = 72x – y = 07x + 11y = 4° x + 3y – z = 1§c) ¢ 2x + z = 2d)§£ 2y – z = 0°§¢§£x + 3y – z = 12x + z = 22y – z = 5a) 3x – 2y = 5x + 3y = –22x – y = 33 –2| 1 3 |= 11 ? 0 8 ran (A) = 2| A' | = 0 8 ran (A' ) = 2El sistema es compatible.°§¢§£3 –2)3 –2 5)A = 1 3 A' = 1 3 –2(2 –1 (2 –1 3b) 4x + 5y = 72x – y = 07x + 11y = 44 5)4 5 7)A = 2 –1 A' = 2 –1 0(7 11 (7 11 4| A' | = 147 ? 0 8 ran (A' ) = 3 ? ran (A) = 2El sistema es incompatible.Unidad 3. <strong>Resolución</strong> <strong>de</strong> <strong>sistemas</strong> <strong>mediante</strong> <strong>de</strong>terminantes9

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