УК гд а Уж × в
УК гд а Уж × в
УК гд а Уж × в
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ÈÙØØÒÐÐØÓÚØÓØÖÒØÒÓÑÒØÓÖÓÖÑÙиÛÚ ÔØÖ¿ºÃÅÄÐÖ<strong>×</strong><br />
∏<br />
(1 − u s 0 .us 1 .us 2 )2 (1 − u s−1<br />
s≥1<br />
−<br />
=<br />
∑<br />
r j ≡0(ÑÓ3)<br />
∑<br />
r 1 =1,r 2 =0,r 3 =2(ÑÓ3)<br />
+ ∑<br />
0 .u s 1 .us−1<br />
2 )(1 − u s−1<br />
0 .u s−1<br />
1 .u s 2 )<br />
<strong>×</strong> (1 − u s−1<br />
0 .u s 1 .us 2 )(1 − us 0 .us−1 1 .u s 2 )(1 − us 0 .us 1 .us−1 2 )<br />
u 1 6 (r 1(r 1 −2)+r2 2+r 3(r 3 +2))<br />
0 u 1 6 (r2 1 +r 2(r 2 +2)+r 3 (r 3 −2))<br />
1 u 1 6 (r 1(r 1 +2)+r 2 (r 2 −2)+r3 2)<br />
2<br />
u 1 6 (r 1(r 1 +2)+r2 2+r 3(r 3 −2))<br />
0 u 1 6 (r 1(r 1 −2)+r 2 (r 2 +2)+r3 2)<br />
1 u 1 6 (r2 1 +r 2(r 2 −2)+r 3 (r 3 +2))<br />
2<br />
u 1 6 (r 1(r 1 +2)+r 2 (r 2 −2)+r3 2)<br />
0 u 1 6 (r 1(r 1 −2)+r2 2+r 3(r 3 +2))<br />
1 u 1 6 (r2 1 +r 2(r 2 +2)+r 3 (r 3 −2))<br />
2<br />
r j ≡1(ÑÓ3)<br />
∑<br />
r 1 =0,r 2 =2,r 3 =1(ÑÓ3)<br />
ÓÙÖ<strong>×</strong>ØÙÝÓØÒÓÑÒØÓÖÒØØÝÓÖÒÄÐÖ<strong>×</strong>ºÏ<strong>×</strong>ÓÛØÑÓØÓÒ<strong>×</strong><br />
r j ≡2(ÑÓ3)<br />
ØØÓÙÖÙØÓØÔÖ<strong>×</strong>ÒÓØÑÒÖÝÖÓÓغÏÒÜØ<strong>×</strong>ØÙÝØÒÓÑÒØÓÖ<br />
)ÌØÓÑÔÐØ<strong>×</strong><br />
ÒØØÝÓÖÃÅÄ<strong>×</strong>ÙÔÖÐÖ<strong>×</strong>ºÌ<strong>×</strong>Û<strong>×</strong>Ö<strong>×</strong>ØÓÒ<strong>×</strong>ØÖÙØÝÓÖÖ<strong>×</strong>ºÏÛÐÐ<strong>×</strong>ØØ<br />
r 1 =2,r 2 =1,r 3 =0(ÑÓ3)<br />
ØÒÓÑÒØÓÖÒØØÝÒØ<strong>×</strong>ÙÔÖ¹ÒÓÑÒØÓÖÒØØÝÓÖÃÅÄ<strong>×</strong>ÙÔÖÐÖ<strong>×</strong><br />
ÛÖr 1 , r 2 , r 3 ∈ Z¸Òm= (r 3 2 − r 3 )n = 1(r 3 1 − r 2 )q= 1(r 3 3 − r<br />
ÒØÖÖ<strong>×</strong>ÖÖØÓØÐØÖØÙÖº ÒÜÔÐÒÓÛØ<strong>×</strong>ÓØÒ<strong>×</strong>ÒÖÐÞØÓÒÓØÒÓÑÒØÓÖÒØØÝÓÖÒÄ ÐÖ<strong>×</strong>º<strong>×</strong>Ù<strong>×</strong><strong>×</strong>ÒÜÑÔÐ<strong>×</strong>ÓÃÅÄ<strong>×</strong>ÙÔÖÐÖ<strong>×</strong><strong>×</strong>ÝÓÒØ<strong>×</strong>ÓÔÓØ<strong>×</strong>ÛÓÖ<br />
1<br />
ÝÔÖÔÐÒÔÖÔÒÙÐÖØÓαÛÒα<strong>×</strong>ÒÚÒ´Ö<strong>×</strong>ÔºÓµÖÓÓØÓÒÓÒ¹ÞÖÓÒÓÖѺÓÖÐÐ ÌÓÒØÏÝйùÓÖÖ<strong>×</strong>ÒÓÑÒØÓÖÓÖÑÙÐÛÖ<strong>×</strong>ØÒØÓÒØ´ÚÒµ αÐÓÒ ÏÝÐÖÓÙÔÓÃÅÄ<strong>×</strong>ÙÔÖÐÖº<strong>×</strong>ÓÖ¸ÛÒØÖØÓÒw ÀÖÓÖØÓÚÓÖÑÙÐØÓÓÐØÖÓÓØ<strong>×</strong>αÖÐ<strong>×</strong>ÓÖÕÙÖØÓ<strong>×</strong>Ø<strong>×</strong>ÝØØÓÒÐ ´¿º½½µ ÛØ<strong>×</strong>β∈ HÖC (α)<br />
(α,α)<br />
(α) 1 .<br />
(α,α)<br />
½¼<br />
−<br />
−<br />
+ ∑<br />
∑<br />
u 1 6 (r 1(r 1 −2)+r 2 (r 2 +2)+r3 2)<br />
0 u 1 6 (r2 1 +r 2(r 2 −2)+r 3 (r 3 +2))<br />
1 u 1 6 (r 1(r 1 +2)+r2 2+r 3(r 3 −2))<br />
2<br />
u 1 6 (r2 1 +r 2(r 2 +2)+r 3 (r 3 −2))<br />
0 u 1 6 (r 1(r 1 +2)+r 2 (r 2 −2)+r3 2)<br />
1 u 1 6 (r 1(r 1 −2)+r2 2+r 3(r 3 +2))<br />
2<br />
1<br />
⊗ Z Q<br />
u 1 6 (r2 1 +r 2(r 2 −2)+r 3 (r 3 +2))<br />
0 u 1 6 (r 1(r 1 +2)+r2 2+r 3(r 3 −2))<br />
1 u 1 6 (r 1(r 1 −2)+r 2 (r 2 +2)+r3 2)<br />
2 ,<br />
w α (β) =<br />
{<br />
β −<br />
2(β,α)<br />
β − 2(β,α)<br />
= 0 ,<br />
=