УК гд а Уж × в
УК гд а Уж × в
УК гд а Уж × в
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ÔØÖ¿ºÃÅÄÐÖ<strong>×</strong><br />
2µºÅÓÖÒÖÐÐÝ ÒÚØÓÖÓÖρ(h)ÛØÒÚÐÙα ÌÓÔÖØÓÖ<strong>×</strong>ρ(x)Òρ(y)ÖÐÐØÖ<strong>×</strong>ÒÒÐÓÛÖÒÓÔÖØÓÖ<strong>×</strong>Ö<strong>×</strong>ÔØÚÐݸ ´¿º½µ<br />
+ 2´Ö<strong>×</strong>Ôºα −<br />
<strong>×</strong>ØÒØÒÚÐÙ<strong>×</strong>¸ØÓÔÖØÓÒÓÖ<strong>×</strong>ÒØÒÚÐÙÝÔÔÐÝÒØρ(x)ÓÔÖØÓÖ ÌÓÔÖØÓÖρ(x)ÓÔÖØÒÓÒÒعÑÒ<strong>×</strong>ÓÒÐÚØÓÖ<strong>×</strong>ÔÒÚÓÒÐÝÒØÐÝÑÒÝ <strong>×</strong>ÒØÝÚØØÓ¸Ö<strong>×</strong>ÔØÚÐݸÖ<strong>×</strong>ÒÒÐÓÛÖÒØÒÚÐÙÓρ(h)Ý2º<br />
ÒÒÓØÖÔØÒÒØÐÝÒÑÙ<strong>×</strong>ØØÖÑÒØØÖÒØÒÙÑÖÓÓÔÖØÓÒ<strong>×</strong>ºÌÙ<strong>×</strong><br />
0<strong>×</strong>ÙØØ ØÖÛÐÐÜ<strong>×</strong>Ø<strong>×</strong>ÓÑÒØÖN ≥<br />
2N¸ØÓÚÕÙØÓÒ<strong>×</strong>ÒÛÖØØÒ<strong>×</strong><br />
ρ(x) N u ≠ 0 ,<br />
ÒÒu v<strong>×</strong>Ø<strong>×</strong>ØÒÚÐÙÓρ(h)ÒØÚÒÖÔÖ<strong>×</strong>ÒØØÓÒ¸ÒÒÝÙÖØÖÓÔÖØÓÒÝ<br />
0<br />
´¿º½µ<br />
= ρ(x) N uÒv=<br />
0¸ÓÖk≥0ÛÚ<br />
0ÓÒÒÔÔÐÝØÓÔÖØÓÖρ(y)ØÓÐÓÛÖØ<strong>×</strong>ÒÚÐÙÝ2º<br />
+<br />
ρ(x)u 0 = 0 .<br />
ρ(x)Ú<strong>×</strong>0ºÌÓØÚØÓÖu ÒÒu k<br />
´¿º½µ<br />
= ρ(y) k u<br />
ÒÓÒ¹ÞÖÓºÌÖÑÙ<strong>×</strong>ظØÖÓÖ¸Ü<strong>×</strong>ØÒÓÒ¹ÒØÚÒØÖm<strong>×</strong>ÙØØ k³<strong>×</strong>ÒÒÓØÐÐ<br />
ρ(x)u k = [kv − k(k − 1)]u k−1 .<br />
Ò¸ØÓÔÖØÓÒÓÐÓÛÖÒÒÒÓØÖÔØÒÒØÐݸÒØu m¸ÙØ<br />
¾<br />
ÓÖÐÐk≤<br />
u<br />
ÙØ<br />
ρ(x)<br />
α<br />
ρ(h)ρ(x) n u = (α + 2n)ρ(x) n u ,<br />
ρ(h)ρ(y) n u = (α − 2n)ρ(y) n u .<br />
N+1 u = 0 .<br />
ρ(h)u 0 = v u 0 ,<br />
ρ(h)u k = (v − 2k)u k ,<br />
u k = ρ(y) k u 0 ≠ 0 ,<br />
m+1 = ρ(y) m+1 u 0 = 0 .
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