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mºÁÒØÖÑ<strong>×</strong>ÓØ<strong>×</strong><strong>×</strong>´¿ºµØÓÚÓÖÑÙÐÓÑ<strong>×</strong> ÔØÖ¿ºÃÅÄÐÖ<strong>×</strong><br />

ÌÙ<strong>×</strong>¸<br />

<strong>×</strong>ÔV ´¿º½¿µ<br />

<strong>×</strong>ÓÒÐÞк ºÌÙ<strong>×</strong>¸Û<br />

ÓÖÖ<strong>×</strong>ÔÓÒÒØÓØÐÑÒØ<strong>×</strong>xÒyÛÚØÓÐÐÓÛÒÓÔÖØÓÖ<strong>×</strong><br />

ÌØÓÒÓρ m (h)ÓÒ<strong>×</strong><strong>×</strong>ÐÑÒØz <strong>×</strong>ρ 2 2<br />

<strong>×</strong>ØØzk <strong>×</strong>ÒÒÚØÓÖÓÖρ (h)ÛØÒÚÐÙ(m 2k)ºÁÒÔÖØÙÐÖ¸ρ 2<br />

<strong>×</strong>ÓØØ<br />

´¿º½µ<br />

m<strong>×</strong>ØÖØ<strong>×</strong>ÙÑÓØ<strong>×</strong>ÛØ<strong>×</strong>Ô<strong>×</strong>ºÌÖÔÖ<strong>×</strong>ÒØØÓÒ ÖÒÚØÓÖ<strong>×</strong>Óρ(h)¸ÒÓÛÒØØÓÒÓ 0º<br />

2 .<br />

ÆÓØØظ<strong>×</strong>ÒÐÐØ<strong>×</strong><strong>×</strong>ÚØÓÖ<strong>×</strong>zk 2<br />

<strong>×</strong>ÝØÓ<strong>×</strong>ØØØÓÖÖ<strong>×</strong>ÔÓÒÒÓÔÖØÓÖ<strong>×</strong>ØÓÒÒÒÚØÓÖuÓρ(h)<strong>×</strong>ÓÐÐÓÛ<strong>×</strong> ÛØØ<strong>×</strong>ÑÑÒ<strong>×</strong>ÓÒÖÕÙÚÐÒغ<br />

ρ(h)ÓÒØ<strong>×</strong><strong>×</strong>ÚØÓÖ<strong>×</strong>Ú<strong>×</strong>V ρ m<strong>×</strong>ÒÖÖÙÐÖÔÖ<strong>×</strong>ÒØØÓÒÓsl(2,<br />

xÒy<strong>×</strong>ÚÒÓÚ¸Ø<strong>×</strong><br />

C)ÒØÖ<strong>×</strong>ÓÒ<strong>×</strong>ÙÓÖÒØÖm ≥<br />

ÌÖÔÖ<strong>×</strong>ÒØØÓÒρ m<strong>×</strong>ÑÒ<strong>×</strong>ÓÒm + 1ºÒÝØÛÓÖÖÙÐÖÔÖ<strong>×</strong>ÒØØÓÒ<strong>×</strong>Ósl(2,<br />

´¿º½µ<br />

ÚÒØÓÑÑÙØØÓÒÖÐØÓÒ<strong>×</strong>ØÛÒØÐÑÒØ<strong>×</strong>h,<br />

ËÒÛÖÛÓÖÒÓÚÖÒÐÖÐÐÝÐÓ<strong>×</strong>иC¸ØÓÚÕÙØÓÒ<strong>×</strong>Ý<strong>×</strong>ØØÚÒ<br />

0µÓÖρ(x)u´Ö<strong>×</strong>Ôºρ(y)uµ<strong>×</strong>Ò ÒÒÚØÓÖuÓρ(h)¸ØÖρ(x)u = 0´Ö<strong>×</strong>Ôºρ(y)u ½<br />

(ρ m (h)f)(z) = −z 1<br />

∂f<br />

∂z 1<br />

+ z 2<br />

∂f<br />

∂z 2<br />

.<br />

∂ ∂<br />

ρ m (h) = −z 1 + z 2 .<br />

∂z 1 ∂z 2<br />

1 kzm−k<br />

m<br />

1 zm−k<br />

m<br />

ρ m (x) = −z 2<br />

∂<br />

∂z 1<br />

,<br />

−<br />

ρ m (x)z1 k zm−k 2 = −k z k−1<br />

m (h)<br />

(h) z k 1 zm−k 2 = (m−2k)z k 1 zm−k<br />

ρ m (y) = −z 1<br />

∂<br />

∂z 2<br />

,<br />

1 z2 m−k+1 ,<br />

ρ m (y)z1 k zm−k 2 = (k − m) z k+1<br />

1 zm−k<br />

1 z m−k−1<br />

C)<br />

ρ(h)ρ(x)u = (α + 2)ρ(x)u ,<br />

ρ(h)ρ(y)u = (α − 2)ρ(y)u .<br />

=

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