УК гд а Уж × в
УК гд а Уж × в
УК гд а Уж × в
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ÔØÖºÃÅÄ<strong>×</strong>ÙÔÖÐÖ<strong>×</strong>ÖÓÑÝÓÒËÔØÖ<br />
ÏÛÐÐÖ<strong>×</strong>Ø<strong>×</strong>ÓÛØØØÓÒØÒ<strong>×</strong>ÐÐØÖÐ<strong>×</strong>ÑÔÐÖÓÓØ<strong>×</strong>ØØÓÒÜÔØ<strong>×</strong>ÖÓÑØ<strong>×</strong>ØÙÝ ÓØÛÐÐ<strong>×</strong>ÓÑÖÒÐ<strong>×</strong>ØÐØݺÍ<strong>×</strong>ÒØÒØÓÒÓØÚÒÒÙ<strong>×</strong>¹ØÛÓØØÓÒ<strong>×</strong>ØÒØ<strong>×</strong>¸<br />
(Z)Ú<strong>×</strong>Ö<strong>×</strong>ØÓØÒÓÑÒØÓÖÒØØÝÓÖØ<strong>×</strong>ÃÅÄ<strong>×</strong>ÙÔÖÐÖº<br />
(Z)º<br />
∞¹ÁÒÚÖÒÓ˜∆3/2 ÄØÙ<strong>×</strong><strong>×</strong>˜∆3/2<br />
ÓÒÒ<strong>×</strong>ÐÝÔÖÓÚØÓÐÐÓÛÒØÛÓÒØØ<strong>×</strong>ÓÙؘ∆3/2 )ºÌÒ¸˜∆3/2 ½ºÄØZ ′ −z 2 z 3 ′ ) = −˜∆ 4º ´º¿¿µ<br />
3/2<br />
3ºÌ<strong>×</strong>ÑÔÐ<strong>×</strong>ØØØÑÓÙÐÖÓÖÑ<br />
(Z) .<br />
Ì<strong>×</strong>ÑÔÐ<strong>×</strong>ØØØÑÓÙÐÖÓÖÑ<strong>×</strong>ÒÓÙÒØÓÒÙÒÖr →<br />
¾º˜∆3/2 (Z)<strong>×</strong>ÒÚÖÒØÙÒÖØÜÒz ↔ 4z<br />
mÛÖØØÒ<strong>×</strong>2<strong>×</strong>2ÑØÖÜ<strong>×</strong>ÓÐÐÓÛ<strong>×</strong> ´º¿µ<br />
<strong>×</strong>ÒÓÙÒØÓÒÙÒÖØÜÒq↔ s<br />
ÆÜظØD ∞¹ÒÖØÓÖ<strong>×</strong>γÒδØÓÒØÖÓÓØ<strong>×</strong>x (2)<br />
(Z)<strong>×</strong>ÒÚÖÒØÙÒÖØ<strong>×</strong>ÝÑÑØÖÝÒÖØ ´º¿µ ÌÑØÖÜγ<strong>×</strong>ÒÓØÝγ ÇÒÒ<strong>×</strong>ÓÛØØØ<strong>×</strong>ÒÑÙ<strong>×</strong>Ø+1ÝÓ<strong>×</strong>ÖÚÒØØÒÝÔÖÓØÖÑ<strong>×</strong>ÒØÓÙÖÖ<br />
(4)Ò℄º˜∆3/2 ÝØÑÒÓγÒδÒØÓG 0 (4) ∈ Sp(2, Z)ºÌ<strong>×</strong>ÑÔÐ<strong>×</strong>ØØÙÒÖØØÓÒÓγ<br />
ÝØØÓÒÓδÔÔÖÛØÓÒØ+1ºËÑÐÖÐݸØØÖÑ<strong>×</strong><strong>×</strong><strong>×</strong>ÓØÛØØÖÐ<br />
(Z)ÖÐØÝØØÓÒÓγ´δÖ<strong>×</strong>ÔºµÔÔÖÛØØ<strong>×</strong>ÑÓÙÖÖ 0ÖÐØ ÜÔÒ<strong>×</strong>ÓÒÓ˜∆3/2<br />
ÔÖÓÓØØØÒÒØÖÐ<strong>×</strong>ÑÔÐÖÓÓØ<strong>×</strong>ÚÒÝØÚØÓÖXÐÐÔÔÖÒØÓÙÖÖ<br />
−1ÖÐØÝγ¹ØÖÒ<strong>×</strong>ÐØÓÒÐ<strong>×</strong>ÓÔÔÖÛØÓÒØ+1ºÌÙ<strong>×</strong>¸Û ÓÒغÓÖÒ<strong>×</strong>ØÒ¸ØØÖÑ<strong>×</strong><strong>×</strong><strong>×</strong>ÓØÛØØØÛÓ<strong>×</strong>ÑÔÐÖÓÓØ<strong>×</strong>α 0Òβ <strong>×</strong>ÑÔÐÖÓÓØ<strong>×</strong>β 0Òβ (Z)º<br />
∞ºÌ<strong>×</strong>ÔÖÓÚ<strong>×</strong>ÒÐйÓÖÖ<strong>×</strong><br />
½½<br />
(Z)<strong>×</strong>ÒÚÖÒØÙÒÖØÙÐÐÖÐÖÓÙÔD <strong>×</strong>Øؘ∆3/2 (2)<br />
ÜÔÒ<strong>×</strong>ÓÒÓ˜∆3/2<br />
D (2)<br />
Òδ¸<br />
˜∆3/2<br />
=<br />
(<br />
z 1 −z 2<br />
(Z<br />
1<br />
( ) (<br />
1 −1 1 −1<br />
γ : x m −→ · x m ·<br />
)Ì,<br />
4 −3 4 −3<br />
( ) (<br />
−1 1 −1 1<br />
δ : x m −→ · x m ·<br />
)Ì.<br />
0 1 0 1<br />
(Z) → ± ˜∆ 3/2 (Z) .<br />
r −1º
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