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2Ò<strong>×</strong>Ù<strong>×</strong>ØÚÑÒÒÖ<strong>×</strong>ÓÐÐÓÛ<strong>×</strong> ÔØÖºÓÒ<strong>×</strong>ØÖÙØÒØÅÓÙÐÖÓÖÑ<strong>×</strong> ØØÔÔÖÓÖN =<br />

4<strong>×</strong>ÖØÓÓØÛÓÑÓÙÐÖÓÖÑ<strong>×</strong>¸ÛØ ´º½µ<br />

ØØÖÓØ<strong>×</strong>ØÖÒØÓÖݺÌ<strong>×</strong>ÒØÙÖÐÐÝ<strong>×</strong>Ù<strong>×</strong>ØØØØËÐÑÓÙÐÖÓÖÑÓÖØÝÔÁÁ ØÒÙÑÖØÓÖÓÖÖ<strong>×</strong>ÔÓÒÒØÓØ<strong>×</strong>ÕÙÖÓØÙ<strong>×</strong>ÔÓÖÑÛÓÙÒØ<strong>×</strong>ÐÈË<strong>×</strong>ØØ<strong>×</strong><br />

2ÀÄÑÓÐÒØÒÓÑÒØÓÖ<strong>×</strong>Ù<strong>×</strong>ÔÓÖÑÛÓÙÒØ<strong>×</strong>ÐÈË<strong>×</strong>ØØ<strong>×</strong>Ò<br />

.<br />

ÁÒØ<strong>×</strong>ÓÖÑØ<strong>×</strong>ÚÒØØØØÑÓÙÐÖÓÖÑg 2ÑÓÐ<strong>×</strong>ÖØÓÓËÐÑÓÙÐÖÓÖÑ<strong>×</strong>¸ ÒØZ Z<br />

3<strong>×</strong>ÒÖØÓ¸<strong>×</strong>Ù<strong>×</strong>ØÒØÖÐØÓÒ ´º¾µ<br />

Ψ 2 (Z) = Φ 6(Z) 2<br />

Φ 10 (Z) .<br />

ÇÒÒ<strong>×</strong>ÐÝ<strong>×</strong>ØØÓØØ<strong>×</strong>ÒØØ<strong>×</strong>ÓÐÐÓÛÖÓÑØÔÖÓÙØÓÖÑÙÐÙ<strong>×</strong>ÒØ ´º¿µ ÁÒØZ ÖÐØÓÒØÛÒØÝÔÁÁÒÀÄØÛ<strong>×</strong>ØÐÐÔØÒÖÚÒÒÕº´ºµÒ´º¼µº ÙÖØÖ¸ØÐ<strong>×</strong>ÓÓÐÐÓÛ<strong>×</strong>ØØ<strong>×</strong>ÑÐÖÖÐØÓÒ<strong>×</strong>ÔÓÐ<strong>×</strong>ÓÖØÓØÖÑÓÙÐÖÓÖÑ<strong>×</strong>º<br />

3<strong>×</strong>¸ÛÒØØg 4ØÝÔÁÁÑÓдºµ<br />

´ºµ<br />

º<br />

ÏÓÒÐÙØ<strong>×</strong><strong>×</strong>ØÓÒÛØÓÒØÙÖÐÓÖÑÙÐÓÖØN =<br />

ÁÒØ<strong>×</strong>ÔØÖÛÚ<strong>×</strong>ØÙØÚÖÓÙ<strong>×</strong>ÑÓÙÐÖÓÖÑ<strong>×</strong>ØØÔÔÖÒØÓÙØÒÓ ÓÒÐÙ<strong>×</strong>ÓÒ<br />

ÒΨ .<br />

4<strong>×</strong>ØÖÒØÓÖ<strong>×</strong>ØØÛÖ<strong>×</strong>ØÙÝÒÒØ<strong>×</strong>Ø<strong>×</strong><strong>×</strong>ºÌÒÖÝ<br />

∆ 5 (Z)<br />

½ ÝÓÒ<strong>×</strong>ØØ<strong>×</strong>ÒN =<br />

g 4 (τ) = η16 (2τ)<br />

= η16 (2τ)η 16 (τ)<br />

,<br />

η 8 (τ) η 24 (τ)<br />

g 3 (τ) = η9 (3τ)<br />

η 3 (τ) = η9 (3τ)η 9 (τ)<br />

η 12 (τ)<br />

˜Ψ 1 (Z) = ∆ 3(Z)∆ 3/2 (Z) 2<br />

Ψ 1 (Z) = ∆ 2(Z) 3<br />

∆ 5 (Z) ,<br />

˜Ψ 2 (Z) = ˜Φ 6 (Z) 2<br />

Φ 10 (Z)<br />

˜Ψ 1 (Z) = ˜∆ 2 (Z) 3<br />

∆ 5 (Z)<br />

1<br />

(Z) = ˜∆ 3 (Z)˜∆ 3/2 (Z) 2<br />

∆ 5 (Z)

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