УК гд а Уж × в
УК гд а Уж × в
УК гд а Уж × в
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ÔØÖºÓÒ<strong>×</strong>ØÖÙØÒØÅÓÙÐÖÓÖÑ<strong>×</strong> )ºº¸<br />
´º¾µ<br />
ÚÐÙ<strong>×</strong>ÓkÒmºÓÖN = 3¸ÛÒÒÓÒ¹ØÖÚÐÖØÖχψ (d) = ( −3<br />
d<br />
3¸ØÛØÓØÑÓÙÐÖÓÖÑ<strong>×</strong>ÚÒ<strong>×</strong>k=2ºÀÓÛÚÖ¸Ø<strong>×</strong><br />
ψ¸ÓÒÓØÒ<strong>×</strong> ÌÙ<strong>×</strong>¸ÛÒN =<br />
ÂÓÓÖѸψ 2,1/2 (z 1<br />
´º¿µ<br />
, z)¸ØÖÒ<strong>×</strong>ÓÖÑ<strong>×</strong>ÛØÖØÖw w ψØÙ<strong>×</strong>ÚÒØÖ<strong>×</strong>ØÖØÓÒÓÒk ÒÓºÌÒÒØÓÓÙÒØØØÓÒÐÖØÖ¸w , l α α)<br />
ØØÚÐØ<strong>×</strong>ÒÓØÒ<strong>×</strong><strong>×</strong>Öݺ<br />
(Z)ÒÒ<strong>×</strong>ØÔÖÓÙØÓkÚÒÒÙ<strong>×</strong>¹ØÛÓØØÓÒ<strong>×</strong>ØÒØ<strong>×</strong>Ò<br />
q n/2 r l/2 s m/2 , 2<br />
ÛØχψ (α)<strong>×</strong>ÒÒÕº´º¾µÖÔÐÒχ(α)ºÓÖN 1, 2, 4¸ÛÛÐÐ<strong>×</strong>ØØ∆ ÁÒÔØÖ4Û<strong>×</strong>ÛØØËÐÑÓÙÐÖÓÖÑ<strong>×</strong>ÒÜÔÖ<strong>×</strong><strong>×</strong>ÒØÖÑ<strong>×</strong>ÓÔÖÓÙØ<strong>×</strong>ÓÚÒ º¿º ÜÔÖ<strong>×</strong><strong>×</strong>ÓÒ<strong>×</strong>ÒØÖÑ<strong>×</strong>ÓÒÙ<strong>×</strong>¹ØÛÓØØÓÒ<strong>×</strong>ØÒØ<strong>×</strong><br />
<strong>×</strong>ÛÐÐ<strong>×</strong>˜∆k/2<br />
ÑØ<strong>×</strong>ÙÒÜÔÖ<strong>×</strong><strong>×</strong>ÓÒÒÛÚØÖºÏÑÒØÓÒÖÐÖØØØËÐÑÓÙÐÖ ÒÙ<strong>×</strong>¹ØÛÓØØÓÒ<strong>×</strong>ØÒØ<strong>×</strong>ºËÓÑÓØËÐÑÓÙÐÖÓÖÑ<strong>×</strong>ÓÙÖÒÒÓÙÖ<strong>×</strong>ØÙÝÐ<strong>×</strong>Ó<br />
ØØÓÒ<strong>×</strong>ØÒØ<strong>×</strong> (Z)ÒÛÖØØÒ<strong>×</strong>Ø<strong>×</strong>ÕÙÖÔÖÓÙØÓÐÐØÚÒÒÙ<strong>×</strong>¹ØÛÓ ´ºµ ÓÖÑÓÖN = 1¸Φ ØØÓÒ<strong>×</strong>ØÒ<strong>×</strong><strong>×</strong>ÓÐÐÓÛ<strong>×</strong><br />
10<br />
2<br />
(Z)<strong>×</strong>ÔÖÓÙØ<strong>×</strong>ÓÚÒÒÙ<strong>×</strong>¹ØÛÓ<br />
Φ θ m (Z))<br />
≡ [∆5 (Z)] 2 .<br />
ËÑÐÖÐݸÓÖN = 2ÓÒÒÛÖØØÑÓÙÐÖÓÖÑΦ (Z)ØÜÔÖ<strong>×</strong><strong>×</strong>ÓÒ<strong>×</strong>ÚÒÝ ´ºµ<br />
2<br />
θ m (Z))<br />
≡ [∆3 (Z)] 2 ´ºµ<br />
.<br />
m=1ÑÓ2 ÛÐÓÖ˜Φ6<br />
) 2 ] 2<br />
≡<br />
[˜∆3 (Z) ,<br />
½¿<br />
∆ 2 (Z) =<br />
⎧<br />
⎪⎨ 0 d = 0 mod 3 ,<br />
χ ψ (d) = 1 d = 1 mod 3 ,<br />
⎪⎩<br />
−1 d = 2 mod 3 .<br />
γ<br />
∑<br />
(n,l,m)>0<br />
∑<br />
α|(n, l, m)<br />
α > 0<br />
χ ψ (α) α k−1 g ( nm<br />
=<br />
( 1<br />
10 (Z) =<br />
64<br />
9∏<br />
m=0<br />
6<br />
Φ 6 (Z) =<br />
( 1<br />
64 θ 2(Z)<br />
∏<br />
˜Φ 6 (Z) =<br />
( 1<br />
16 θ 1(Z) θ 3 (Z) θ 6 (Z) θ 7 (Z) θ 8 (Z) θ 9 (Z)<br />
k/2 (Z)
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