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CONTINUUM MECHANICS for ENGINEERS

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Answer: (a)<br />

(b)<br />

2 2<br />

(c) (1) a1a 2a 3 = 1, (2) 9a1+ a2= 2a<br />

4.30 A homogeneous de<strong>for</strong>mation is defined by<br />

x 1 = αX 1 + βX 2, x 2 = –αX 1+ βX 2, x 3 = µX 3<br />

where α, β and µ are constants.<br />

Determine<br />

(a) the magnitudes and directions of the principal stretches<br />

(b) the matrix representation of the rotation tensor R<br />

(c) the direction of the axis of the rotation vector, and the magnitude<br />

of the angle of rotation.<br />

2 2 2 2 2 2<br />

Answer: (a) Λ Λ , ,<br />

( 1)<br />

= = 2α<br />

Λ Λ<br />

eˆ<br />

( 2)<br />

= = 2β<br />

eˆ<br />

(b)<br />

l2<br />

= 9a<br />

+ a + a<br />

cosθ =<br />

(c) ; Φ = 45°<br />

4.31 Consider the de<strong>for</strong>mation field<br />

x1 = X1 – AX2 + AX3 ˆ n= Iˆ<br />

3<br />

2<br />

1<br />

x 2 = X 2 – AX 3 + AX 1<br />

x 3 = X 3 – AX 1 + AX 2<br />

where A is a constant. Show that the principal values of the right<br />

stretch tensor have a multiplicity of two, and that the axis of the<br />

rotation tensor is along Nˆ = ˆ ˆ ˆ ( I1+ I2 + I3)<br />

/ 3 . Determine the matrix<br />

of the rotation vector together with the angle of rotation Φ.<br />

2<br />

Answer: Λ ( 1) = 1, Λ( 2) = Λ(<br />

3)<br />

= 1+ 3A=<br />

β<br />

Φ = cos –1 (1/β)<br />

2<br />

2<br />

2a<br />

1<br />

2<br />

3<br />

2<br />

4a<br />

+ a<br />

( 1)<br />

1<br />

2<br />

2<br />

⎡ 1/ 2 1/ 2 0⎤<br />

⎢<br />

⎥<br />

Rij = ⎢−1/<br />

2 1/ 2 0⎥<br />

⎢<br />

⎥<br />

⎣<br />

0 0 1<br />

⎦<br />

( 2 )<br />

A A<br />

Rij<br />

A A<br />

A A<br />

=<br />

⎡ β + 2 β −1−3 β − 1+ 3 ⎤<br />

1 ⎢<br />

⎥<br />

⎢<br />

β − 1+ 3 β + 2 β −1−3 3β<br />

⎥<br />

⎣<br />

⎢β<br />

−1−3 β − 1+ 3 β<br />

+ 2 ⎦<br />

⎥<br />

2<br />

3<br />

2 2 2<br />

Λ( 3)<br />

= Λ = µ<br />

eˆ<br />

( 3 )

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