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CONTINUUM MECHANICS for ENGINEERS

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Using indicial notation, show that,<br />

(a) v · v = a2b2sin2θ (b) a × b · a = 0<br />

(c) a × b · b = 0<br />

2.2 With respect to the triad of base vectors u1, u2, and u3 (not necessarily<br />

unit vectors), the triad u1 , u2 , and u3 is said to be a reciprocal basis if<br />

ui ⋅ uj = δij (i, j = 1, 2, 3). Show that to satisfy these conditions,<br />

u1 = ; u2 = ; u3 u2 × u3<br />

u3 × u1<br />

=<br />

u,u, u u,u, u<br />

and determine the reciprocal basis <strong>for</strong> the specific base vectors<br />

u 1 =<br />

u 2 =<br />

u 3 =<br />

Answer: u1 =<br />

u2 =<br />

u3 1<br />

( 3eˆ1−eˆ2 −2eˆ3)<br />

5<br />

1<br />

( − eˆ1+ 2eˆ2<br />

−eˆ3)<br />

5<br />

1<br />

= ( − eˆ + 2ˆ + 4ˆ<br />

1 e2 e3)<br />

5<br />

2.3 Let the position vector of an arbitrary point P(x1x2x3) be x = xeˆ<br />

i i,<br />

and<br />

let b = beˆ<br />

be a constant vector. Show that (x – b) ⋅ x = 0 is the vector<br />

i i<br />

equation of a spherical surface having its center at x = b with a<br />

radius of b.<br />

[ 1 2 3]<br />

1<br />

2<br />

veˆ = a eˆ × b eˆ =εa<br />

b eˆ<br />

i i j j k k ijk j k i<br />

1<br />

[ 1 2 3]<br />

ˆ ˆ<br />

2e1+ e2<br />

ˆ ˆ<br />

2e2 − e3<br />

eˆ + eˆ + eˆ<br />

1 2 3<br />

2.4 Using the notations A (ij) = (Aij + Aji) and A [ij] = (Aij – Aji) show that<br />

2<br />

2<br />

(a) the tensor A having components Aij can always be decomposed<br />

into a sum of its symmetric A (ij) and skew-symmetric A [ij] parts,<br />

respectively, by the decomposition,<br />

A ij = A (ij) + A [ij]<br />

u1× u2<br />

u,u, u<br />

[ 1 2 3]<br />

1<br />

1<br />

2

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