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CONTINUUM MECHANICS for ENGINEERS

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FIGURE 3.5<br />

Free body diagram of tetrahedron element having its vertex at P.<br />

where *bi is an average body <strong>for</strong>ce which acts throughout the body. The negative<br />

signs on the coordinate-face tractions result from the outward unit normals on<br />

those faces pointing in the negative coordinate axes directions. (Recall that<br />

t<br />

( −nˆ)<br />

t<br />

( nˆ<br />

=−<br />

)<br />

). Taking into consideration Eq 3.3-3, we can write Eq 3.3-4 as<br />

i i<br />

(3.3-5)<br />

*<br />

if we permit the indices on the unit vectors of the t<br />

( ê j )<br />

i term to participate<br />

in the summation process. The volume of the tetrahedron is given by dV =<br />

1<br />

h dS, where h is the perpendicular distance from point P to the base ABC.<br />

3<br />

Inserting this into Eq 3.3-5 and canceling the common factor dS, we obtain<br />

(3.3-6)<br />

Now, letting the tetrahedron shrink to point P by taking the limit as h → 0<br />

and noting that in this limiting process the starred (averaged) quantities take<br />

on the actual values of those same quantities at point P, we have<br />

j<br />

or, by defining ≡ t<br />

( ê )<br />

,<br />

σ ji i<br />

t<br />

( )<br />

dS- t<br />

( )<br />

n dS + ρ b dV = 0<br />

* nˆ<br />

* eˆ<br />

j<br />

*<br />

i i j i<br />

t<br />

( )<br />

= t<br />

( ) 1<br />

n − bh<br />

3 ρ<br />

* nˆ<br />

* eˆ<br />

j<br />

*<br />

i i j i<br />

t<br />

( nˆ<br />

) eˆ<br />

j<br />

=t<br />

( )<br />

n<br />

i i j<br />

(3.3-7)<br />

t<br />

( ˆn )<br />

= σ n or t<br />

( n ˆ )<br />

= nˆ⋅σ<br />

(3.3-8)<br />

i ji j<br />

which is the Cauchy stress <strong>for</strong>mula. We can obtain this same result <strong>for</strong> bodies<br />

which are accelerating by using the conservation of linear momentum<br />

instead of a balance of <strong>for</strong>ces on the tetrahedron of Figure 3.5.

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