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CONTINUUM MECHANICS for ENGINEERS

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an expression <strong>for</strong> u i in terms of the proposed potentials into the Navier<br />

equations we obtain the governing equations <strong>for</strong> the appropriate potentials.<br />

Often such potentials are harmonic, or bi-harmonic functions. We shall<br />

present three separate methods <strong>for</strong> arriving at solutions of the Navier equations.<br />

The method used in our first approach rests upon the well-known theorem<br />

of Helmholtz which states that any vector function that is continuous and<br />

finite, and which vanishes at infinity, may be resolved into a pair of components:<br />

one a rotation vector, the other an irrotational vector. Thus, if the curl<br />

of an arbitrary vector a is zero, then a is the gradient of a scalar φ, and a is<br />

irrotational, or as it is sometimes called, solenoidal. At the same time, if the<br />

divergence of the vector a is zero, then a is the curl of another vector ψ, and<br />

is a rotational vector. Accordingly, in keeping with the Helmholtz theorem,<br />

we assume that the displacement field is given by<br />

(6.9-7)<br />

where φ ,i is representative of the irrotational portion, and curl ψ the rotational<br />

portion. Substituting this displacement vector into Eq 6.9-4 with b i in that<br />

equation taken as zero, namely<br />

we obtain<br />

which reduces to<br />

ui = φ, i + εipqψq, p<br />

( ) = 0<br />

µ u + λ + µ u<br />

ijj , jji ,<br />

( ) + ( + ) = 0<br />

µφ + µε ψ + λ + µ φ λ µ ε ψ<br />

, ijj ipq q, pjj , ijj jpq q, pji<br />

( λ + 2µ ) φ + µε ψ = 0<br />

, ijj ipq q, pjj<br />

since ε ψ = 0.<br />

In coordinate-free notation Eq 6.9-10 becomes<br />

jpq q, pji<br />

λ µ φ µ ψ<br />

+<br />

2 2<br />

( 2 ) + × = 0<br />

(6.9-8)<br />

(6.9-9)<br />

(6.9-10)<br />

(6.9-11)<br />

Any set of φ and ψ which satisfies Eq 6.9-10 provides (when substituted into<br />

Eq 6.9-7) a displacement field satisfying the Navier equation, Eq 6.9-8.<br />

Clearly, one such set is obtained by requiring φ and ψ to be harmonic<br />

2<br />

2<br />

φ = 0<br />

ψ =<br />

0<br />

(6.9-12a)<br />

(6.9-12b)

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