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CONTINUUM MECHANICS for ENGINEERS

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θ =<br />

η<br />

∂u<br />

∂<br />

(5.8-2)<br />

Furthermore, partial differentiation of the internal energy with respect to the<br />

thermodynamic substate variables results in thermodynamic tensions<br />

(5.8-3)<br />

The preceding equations can be used to write a differential <strong>for</strong>m of the<br />

internal energy as follows:<br />

(5.8-4)<br />

From Eqs 5.8-1 and 5.8-2 we see that both temperature and thermodynamic<br />

tensions are functions of entropy and the substate parameters.<br />

Assuming that all the functions defined in the section are continuously<br />

differentiable as many times as necessary, it is possible to solve <strong>for</strong> entropy<br />

in terms of temperature<br />

(5.8-5)<br />

This result may be substituted into the caloric equation of state to yield<br />

internal energy as a function of temperature and substate parameters<br />

(5.8-6)<br />

Using this result in Eq 5.8-3 allows the definition of the thermal equations<br />

of state<br />

which inverts to give the substate parameters<br />

τ a<br />

u<br />

= ∂<br />

∂v<br />

du = θdη+∑τ dv<br />

(5.8-7)<br />

(5.8-8)<br />

The principles of thermodynamics are often posed in terms of thermodynamic<br />

potentials which may be defined as follows:<br />

a<br />

a<br />

η= η( θ,va)<br />

u= u( θ,va)<br />

τ τ θ,v<br />

= ( )<br />

a a a<br />

v v<br />

= ( θτ ,<br />

)<br />

a a a<br />

a a

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