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CONTINUUM MECHANICS for ENGINEERS

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FIGURE 3.15A<br />

Reference angles φ and β <strong>for</strong> intersection point Q on surface of body octant.<br />

FIGURE 3.15B<br />

Mohr’s semicircle <strong>for</strong> stress state displayed in Figure 3.15A.<br />

along the circle arc KD of Figure 3.15A. For this case, Eq 3.8-2a becomes<br />

(σN – σII)(σN – σIII) + = (σI – σII)(σI – σIII) cos2φ1, which may be cast into<br />

the standard <strong>for</strong>m of a circle as<br />

σ 2<br />

S<br />

2<br />

2<br />

⎞⎤<br />

2<br />

N II III S I II I III II III R ⎠ 1<br />

⎡ 1 ⎛<br />

⎞⎤<br />

2 2 ⎡1<br />

σ − ⎝σ<br />

+ σ ⎠ + σ = ( σ −σ<br />

) ( σ − σ ) cos φ + ⎛<br />

1 σ −σ<br />

⎣⎢<br />

⎦⎥<br />

⎣<br />

⎢ ⎝<br />

2<br />

2<br />

⎦<br />

⎥ =<br />

(3.8-9)<br />

This circle is seen to have its center coincident with that of circle C1 in stress<br />

space and to have a radius R1 indicated by Eq 3.8-9. There<strong>for</strong>e, as Q moves<br />

on circle arc KD in Figure 3.15A, the stress point q traces the circle arc kd<br />

π<br />

shown in Figure 3.15B. (Notice that if φ1 = so that cos φ1 = 0, R1 reduces<br />

2<br />

1<br />

π<br />

to ( σ σ , the radius of circle C1.) Next, let β = β1 < and then, as φ<br />

II − III)<br />

2 2

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