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CONTINUUM MECHANICS for ENGINEERS

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Solution<br />

For this stress state, the determinant Eq 3.6-5 is given by<br />

σ − σ σ<br />

o o<br />

σo σo − σ<br />

0 0<br />

which results in a cubic having roots (principal stress values) σ (1) = 2σ o, σ (2) =<br />

σ (3) = 0 (as may be readily verified by Eq 3.9-4) so that, in principal axes <strong>for</strong>m,<br />

the stress matrix is<br />

The Mohr’s circle diagram is shown in Figure E3.9-1.<br />

Here, because of the double-zero root, one of the three Mohr’s circles<br />

degenerates into a point (the origin) and the other two circles coincide. Also,<br />

*<br />

we note that physically this is simply a one-dimensional tension in the x1 direction and that the maximum shear stress values (shown by points A and<br />

B) occur on the x1 and x2 coordinate planes which make 45° with the principal<br />

* direction.<br />

x 1<br />

3.10 Deviator and Spherical Stress States<br />

The arithmetic mean of the normal stresses,<br />

(3.10-1)<br />

is referred to as the mean normal stress. The state of stress having all three<br />

principal stresses equal (and there<strong>for</strong>e equal to σ M) is called a spherical state<br />

of stress, represented by the diagonal matrix<br />

0<br />

0<br />

−σ<br />

⎡2σ0<br />

0⎤<br />

* ⎢<br />

⎥<br />

[ σ ij]=<br />

⎢<br />

0 0 0<br />

⎥<br />

⎣<br />

⎢ 0 0 0⎦<br />

⎥<br />

= 0<br />

1<br />

1<br />

σ M = ( σ11 + σ22 + σ33)= σii<br />

3<br />

3<br />

⎡σ<br />

M 0 0 ⎤<br />

⎢<br />

⎥<br />

[ σ ij]=<br />

⎢<br />

0 σ M 0<br />

⎥<br />

⎣<br />

⎢ 0 0<br />

σ M ⎦<br />

⎥<br />

(3.10-2)

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