23.03.2013 Views

CONTINUUM MECHANICS for ENGINEERS

CONTINUUM MECHANICS for ENGINEERS

CONTINUUM MECHANICS for ENGINEERS

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

9.28 A viscoelastic body in the <strong>for</strong>m of a block is elastic in dilatation and<br />

obeys the Maxwell law in distortion. The block is subjected to a<br />

pressure impulse σ 11 = –p oδ(t) distributed uni<strong>for</strong>mly over the x 1 face.<br />

If the block is constrained so that ε 22 = ε 33 = 0, determine ε 11(t) and<br />

σ 22(t).<br />

Answer: σ 22(t) = p o[(2G–3K)δ(t)/(3K+4G)–(6G/(3K+4G))e [–3K/(3K+4G)τ]t ]U(t)<br />

ε 11(t) = p o[3δ(t)/(3K+4G)–[4G/(3K+4G)K]e [–3K/(3K+4G)τ]t ]U(t)<br />

9.29 A viscoelastic cylinder is inserted into a snug fitting cavity of a rigid<br />

container. A flat, smooth plunger is applied to the surface x1 = 0 of<br />

the cylinder and <strong>for</strong>ced downward at a constant strain rate ˙ε . 11 ε<br />

If the material is modeled as the three-parameter solid shown in shear<br />

and as elastic in dilatation, determine σ11(t) and σ22(t) during the<br />

downward motion of the plunger.<br />

= o<br />

Answer: σ 11(t) = –ε o[(4Gτ/3)(1–e –t/τ )+(K+4G/3)t]U(t)<br />

σ 22(t) = ε o[(2Gτ/3)(1–e –t/τ )+(–K+2G/3)t]U(t)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!