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CONTINUUM MECHANICS for ENGINEERS

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FIGURE E3.5-1<br />

Rotation of axes x 1 and x 2 by 45° about x 3 axis.<br />

Thus, from Eq 3.5-1 expressed in matrix <strong>for</strong>m, a 45° rotation of axes requires<br />

⎡ 1/ 2 1/ 2 0⎤⎡1<br />

3 2⎤⎡1/<br />

2 −1/<br />

2 0⎤<br />

⎢<br />

⎥ ⎢ ⎥ ⎢<br />

⎥<br />

[ σ ij ′ ] = ⎢−1/<br />

2 1/ 2 0⎥⎢<br />

3 1 0<br />

⎥ ⎢1/<br />

2 1/ 2 0⎥<br />

⎢<br />

⎥<br />

⎣<br />

0 0 1<br />

⎦ ⎣<br />

⎢2<br />

0 −2⎦<br />

⎥ ⎢<br />

⎥<br />

⎣<br />

0 0 1<br />

⎦<br />

⎡ 4 0 2 ⎤<br />

⎢<br />

⎥<br />

= ⎢ 0 −2 − 2⎥<br />

⎢<br />

⎣<br />

2 − 2 −2<br />

⎥<br />

⎦<br />

Example 3.5-2<br />

Assume the stress tensor (in ksi) at P with respect to axes Px 1x 2x 3 is<br />

represented by the matrix<br />

[ σ ij]=<br />

⎡ 18 0 −12⎤<br />

⎢<br />

⎥<br />

⎢<br />

0 6 0<br />

⎥<br />

⎣<br />

⎢−12<br />

0 24⎦<br />

⎥<br />

If the axis makes equal angles with the three unprimed axes, and the<br />

axis lies in the plane of , as shown by the sketch, determine the primed<br />

components of assuming is a right-handed system.<br />

′ x1 ′ x2 xx 1′ 3<br />

Px′ x′ x′<br />

1 2 3<br />

Solution<br />

We must first determine the trans<strong>for</strong>mation matrix [aij]. Let β be the common<br />

angle which x1′ makes with the unprimed axes, as shown by the sketch. Then<br />

a11 = a12 = a13 = cosβ and from the orthogonality condition Eq 2.5-4 with i = j =<br />

1, cosβ = 1 3 . Next, let φ be the angle between and x3. Then a23 = cosφ =<br />

′ x2

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