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CONTINUUM MECHANICS for ENGINEERS

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9.13 For the hereditary integral, Eq 9.5-2<br />

assume σ(t) = est where s is a constant. Let T = t – t′ be the “elapsed<br />

time” of the load application and show that σ(t) = sest where<br />

is the Laplace trans<strong>for</strong>m of J(t).<br />

9.14 Using σ(t) = est as in Problem 9.13, together with the hereditary integral<br />

Eq 9.5-5a<br />

Js () Js ()<br />

2<br />

and the result of Problem 9.13 show that GsJs ()()= 1/<br />

s where Gs<br />

is the Laplace trans<strong>for</strong>m of G(t). Assume s is real.<br />

9.15 Taking the hereditary integrals <strong>for</strong> viscoelastic behavior in the <strong>for</strong>m<br />

Eq 9.5-4<br />

and Eq 9.5-5c<br />

show that <strong>for</strong> the stress loading σ(t) = e st and with T = t – t′, the<br />

expression<br />

results, where here<br />

and<br />

∫<br />

t<br />

( ) ′<br />

( ) ( ′ ) ′<br />

γ()= t J t − t′ dσ t / dt dt<br />

∫<br />

−∞<br />

t<br />

( ) ′<br />

( ) ( ′ ) ′<br />

σ()= t G t − t′ dγ t / dt dt<br />

−∞<br />

()= ()+ ( ′ ) ( − ′ ) ( − ′ )<br />

γ t J σ t σ t dJ t t / d t t dt<br />

o<br />

t<br />

∫ 0<br />

[ ] ′<br />

()= ()+ ( ′ ) ( − ′ ) ( − ′ )<br />

σ t G γ t γ t dG t t / d t t dt<br />

o<br />

t<br />

∫ 0<br />

[ ] ′<br />

()+ ()+ () ()= 0<br />

GAs JBs AsBs<br />

o o<br />

∫ 0<br />

∞<br />

()= ( )<br />

−sT<br />

As e dJ/ dTdT<br />

∫<br />

∞<br />

()= ( )<br />

−sT<br />

Bs e dG/ dTdT<br />

0<br />

()

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