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CONTINUUM MECHANICS for ENGINEERS

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4.32 For the de<strong>for</strong>mation field<br />

x1 = 3 X1 + X2 x 2 = 2X 2<br />

x 3 = X 3.<br />

determine<br />

(a) the matrix representation of the rotation tensor R<br />

(b) the right stretch tensor U and the left stretch tensor V, then show<br />

that the principal values of U and V are equal<br />

(c) the direction of the axis of rotation and the magnitude of the angle<br />

of rotation.<br />

Answer: (a)<br />

R ij =<br />

⎡ 3 + 1 3 −1<br />

0 ⎤<br />

1 ⎢<br />

⎥<br />

⎢−<br />

3 + 1 3 + 1 0<br />

2 2<br />

⎥<br />

⎢<br />

⎥<br />

⎣<br />

0 0 2 2<br />

⎦<br />

(b) Λ (1) = 6 , Λ (2) = 2 , Λ (3) = 1<br />

(c) Nˆ = Iˆ<br />

3 ; Φ = 15°<br />

4.33 Let a displacement field be given by<br />

1<br />

4 1<br />

4 1<br />

4<br />

u 1 = (X 3 – X 2), u 2 = (X 1 – X 3), u 3 = (X 2 – X 1)<br />

Determine<br />

(a) the volume ratio dV/dV°<br />

(b) the change in the right angle between line elements originally along<br />

the unit vectors Nˆ ˆ ˆ ˆ<br />

1 = ( 3I1−2I2 −I3)<br />

/ 14 and<br />

Nˆ = Iˆ + 4Iˆ −5Iˆ<br />

/ 42 . Explain your answer.<br />

( )<br />

2 1 2 3<br />

Answer: (a) dV/dV° = 1.1875<br />

(b) ∆θ = 0°<br />

4.34 Consider again the de<strong>for</strong>mation given in Example 4.9-1, namely<br />

x 1 = 2(X 1 – X 2), x 2 = X 1 + X 2, x 3 = X 3<br />

Determine<br />

(a) the left stretch tensor V<br />

(b) the direction normals of the principal stretches of V.

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