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CONTINUUM MECHANICS for ENGINEERS

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Recall the definition t + = t + a from which it is obvious that dt/dt + = 1. As a<br />

result of this, an expression <strong>for</strong> the velocity under a superposed rigid body<br />

motion is obtained by taking the time derivatives of the bracketed term of<br />

the preceding equation:<br />

Define<br />

or, written an alternative way by post-multiplying by Q jk<br />

(5.10-14)<br />

(5.10-15)<br />

(5.10-16)<br />

Substituting Eq 5.10-16 into the second of Eq 5.10-14 yields an expression <strong>for</strong><br />

the velocity field of a continuum undergoing a superposed rigid body rotation<br />

(5.10-17)<br />

Note that Ω ij is skew-symmetric by taking the time derivative of the orthogonality<br />

condition <strong>for</strong> Q ij. That is,<br />

When the derivatives are taken<br />

v a˙t Q˙ t x Q t x˙<br />

+ = ()+ () + ()<br />

i i im m im m<br />

= a˙ ()+ t Q˙ () t x + Q () t v<br />

i im m im m<br />

()= t Q˙ () t Q () t<br />

Ω ij im jm<br />

() tQ ()= t Q˙ () tQ () tQ ()= t Q˙ () t<br />

Ω ij jk im jm jk ik<br />

˙Q im<br />

+<br />

v = a˙+ Ω Q x + Q v<br />

i i ij jk k im m<br />

d d<br />

[ QimQin]= []= 1 0<br />

dt dt<br />

Q˙ Q + Q Q˙<br />

=0<br />

im in im in<br />

and the definition of used from Eq 5.10-16 substituted into this expression,<br />

it yields<br />

[ ] = 0<br />

Q Ω + Ω Q<br />

im ji ij jm<br />

This is true only if the bracketed term is zero, thus<br />

Ωij =−Ωji<br />

(5.10-18)

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