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CONTINUUM MECHANICS for ENGINEERS

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(c) Calculate the logarithmic stretching, <strong>for</strong> the<br />

element in the current configuration in the direction of<br />

at x = 0.<br />

Answer: (b) a1 = –ω v2, a2 = ω v1, a3 = 0<br />

˙ Λ/ Λ d lnΛ<br />

/ dt<br />

nˆ = ( eˆ + eˆ<br />

1 3) / 2<br />

(c) e –ct cos ω t<br />

1<br />

2<br />

4.43 Show that the velocity field<br />

v 1 = 1.5x 3 – 3x 2, v 2 = 3x 1 – x 3, v 3 = x 2 – 1.5x 1<br />

corresponds to a rigid body rotation, and determine the axis of spin<br />

(the vorticity vector).<br />

Answer: w = eˆ . ˆ ˆ<br />

1+ 15e2 + 3e3<br />

4.44 For the steady velocity field<br />

2<br />

2<br />

v1 = xx,<br />

v2 = 2x x , v3 = 3x1x2x3 determine the rate of extension at (2, 0, 1) in the direction of the unit<br />

vector 4eˆ − 3eˆ / 5.<br />

( )<br />

1 2<br />

Answer: ˙ 48<br />

Λ/ Λ = −<br />

25<br />

4.45 Prove that d( ln J ) dt=<br />

div v and, in particular, verify that this relationship<br />

is satisfied <strong>for</strong> the motion<br />

x 1 = X 1 + ktX 3, x 2 = X 2 + ktX 3, x 3 = X 3 – kt(X 1 + X 2)<br />

where k is a constant.<br />

Answer: = div v = 4k2t/(1 + 2k2t2 )<br />

4.46 Equation 4.10-19 gives the material derivative of dx2 in terms of Dij .<br />

Using that equation as the starting point, show that d2 (dx2 )/dt2 is given<br />

in terms of Dij and its time derivative by<br />

˙ J/J<br />

d2 (dx2 )/dt2 = 2( + vk,i Dkj + vk,j Dik)dxidxj ˙D ij<br />

4.47 A continuum body in the <strong>for</strong>m of the unit cube shown by the sketch<br />

undergoes the homogeneous de<strong>for</strong>mation<br />

x 1 = λ 1X 1, x 2 = λ 2X 2, x 3 = λ 3X 3<br />

where λ 1, λ 2, and λ 3 are constants.<br />

1<br />

2<br />

2<br />

3<br />

= ( )

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