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The Design of Modern Steel Bridges - TEDI

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132 <strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Modern</strong> <strong>Steel</strong> <strong>Bridges</strong><br />

in accordance with the Hencky–Mises yield criterion (i.e. equation (5.27) with<br />

tcr replaced by tl given above), and (ii) plastic hinges occur in the flanges,<br />

which together with the yielded zone WXYZ form a plastic mechanism.<br />

Considering the virtual work done in this mechanism and adding the resistance<br />

<strong>of</strong> the three stages, one obtains the ultimate shear capacity as<br />

Vu ¼ 4Mp<br />

c þ ctwst sin 2 yt þ stbtwðcot yt fÞ sin 2 yt þ t1btw ð5:32Þ<br />

where Mp is the plastic moment <strong>of</strong> resistance <strong>of</strong> the flange, c is the distance <strong>of</strong><br />

the internal plastic hinge (see Fig. 5.22) in one flange from the corner, and st is<br />

the membrane tensile stress, given by equation (5.27), with tl replacing tcr. <strong>The</strong> equilibrium condition <strong>of</strong> the flange between W and X (or between Z<br />

and Y) in Fig. 5.22 leads to<br />

c ¼ 2<br />

rffiffiffiffiffiffiffiffiffi<br />

Mp<br />

; but>j a<br />

sin yt sttw<br />

Putting this expression for c in equation (5.32) leads to the ultimate shear<br />

capacity tu being given by<br />

tu<br />

ty<br />

¼ t1<br />

ty<br />

tu<br />

ty<br />

rffiffiffiffi<br />

pffiffiffiffi<br />

st<br />

þ 5:264 sin yt m<br />

¼ t1<br />

ty<br />

þ 6:928m<br />

f<br />

ty<br />

þðcot yt fÞ sin 2 st<br />

yt<br />

ty<br />

st<br />

þ sin yt cos yt when m5<br />

ty<br />

f2 sin 2 ytst<br />

6:928ty<br />

when m4 f2 sin 2 ytst<br />

6:928ty<br />

ð5:33aÞ<br />

Figure 5.22 Tension-field mechanism <strong>of</strong> Porter, Rockey and Evans[8].<br />

ð5:33bÞ

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