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The Design of Modern Steel Bridges - TEDI

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164 <strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Modern</strong> <strong>Steel</strong> <strong>Bridges</strong><br />

<strong>The</strong> well-known Perry strut equation can be used to obtain the limiting value<br />

<strong>of</strong> the longitudinal stress that can be applied on the effective strut:<br />

ssu<br />

s0 ¼<br />

y<br />

1<br />

1 þð1þ ZÞ<br />

2<br />

sE<br />

s0 ( )<br />

ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi<br />

1 þð1þ ZÞ<br />

y<br />

sE<br />

s0 ( ) 2<br />

4sE<br />

y s0 2<br />

v<br />

3<br />

u<br />

6<br />

t<br />

7<br />

4<br />

5 ð6:2Þ<br />

y<br />

where<br />

ssu ¼ limiting value <strong>of</strong> the applied longitudinal stress on the strut<br />

sE ¼ Euler buckling stress <strong>of</strong> the strut<br />

Z ¼ y/r 2<br />

y<br />

¼ maximum initial eccentricity and imperfection, i.e. (e1 þ e2) ¼ distance <strong>of</strong> the extreme compressive fibre from the centroid <strong>of</strong> the<br />

effective strut cross-section<br />

r ¼ radius <strong>of</strong> gyration <strong>of</strong> the effective strut cross-section<br />

s0 y ¼ available yield stress at the extreme compressive fibre (see Section 6.4).<br />

Because <strong>of</strong> the asymmetry <strong>of</strong> the cross-section about the horizontal centroidal<br />

axis, equation (6.2) must be applied to both the flange plate and the tip<br />

<strong>of</strong> the stiffening rib, with appropriate values for , y and s 0 y .<br />

6.4 Allowance for shear and transverse stress in flange plate<br />

According to Hencky–Mises’ criterion <strong>of</strong> yielding (see Chapter 2), the presence<br />

<strong>of</strong> shear stress in the flange plate reduces its effective yield stress to<br />

s 0 y ¼<br />

ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi<br />

3t2 q<br />

ð6:3Þ<br />

s 2 y<br />

<strong>The</strong> flange shear stress t is caused by (i) the vertical shear force on the crosssection<br />

<strong>of</strong> the main girder, and (ii) in the case <strong>of</strong> a box girder, by applied<br />

torsion on the girder. <strong>The</strong> stress due to (i) varies linearly from a maximum<br />

value over the main girder web to zero mid-way between a pair <strong>of</strong> such webs,<br />

and hence only half the maximum value needs to be taken along with the full<br />

value due to (ii) for t in equation (6.3) for the flange plate initiated failure. For<br />

failure initiated by the tip <strong>of</strong> the stiffeners, the full value <strong>of</strong> the material yield<br />

stress <strong>of</strong> the tip is available in equation (6.2).<br />

In addition to the above influence on yield stress, shear stress due to torsion<br />

on a box girder also causes a destabilising effect on the longitudinal flange<br />

stiffeners. An allowance for this may be made in the form <strong>of</strong> an additional<br />

notional axial load in the same way as derived for web stiffeners in Chapter 5.<br />

Transverse stresses in the flange plate are caused by the flexure <strong>of</strong> the<br />

transverse flange stiffeners, and crossframes and diaphragms in box girders. As<br />

the centroid <strong>of</strong> the cross-section <strong>of</strong> a transverse stiffener is very near the flange<br />

plate, the magnitude <strong>of</strong> the transverse stress is small. When this transverse<br />

stress is compressive, it may in fact increase the effective yield stress in

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