10.04.2013 Views

The Design of Modern Steel Bridges - TEDI

The Design of Modern Steel Bridges - TEDI

The Design of Modern Steel Bridges - TEDI

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

142 <strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Modern</strong> <strong>Steel</strong> <strong>Bridges</strong><br />

For webs stiffened with vertical stiffeners only<br />

Pcro ¼ 2p2<br />

B ðDx DyÞ 1=2 , ignoring H<br />

In this case Dx ¼ Et 3 /12[1<br />

2<br />

], and Dy ¼ EIsy/a, when t is the thickness <strong>of</strong> the<br />

web and is the Poisson’s ratio, equal to 0.3. Hence<br />

Pcro ¼ 6E<br />

B<br />

t 3 Isy<br />

a<br />

We may design a transverse stiffener as a strut with an effective axial load<br />

Peq such that the ratio <strong>of</strong> this effective axial load to the Euler buckling load <strong>of</strong><br />

the strut, P E, is equal to the ratio <strong>of</strong> the longitudinal force on the web to the<br />

orthotropic elastic critical buckling load P cro derived from above, i.e.<br />

wherefrom<br />

Peq<br />

PE<br />

¼ s1tB<br />

Pcro<br />

Peq ¼ s1tB PE<br />

We should also take account <strong>of</strong> the fact that the destabilising forces in the<br />

web do not cause any axial stress on the transverse stiffeners. If a strut with an<br />

initial imperfection i is subjected to a destabilising force Peq that magnifies<br />

the initial imperfection, but does not cause any axial stress, the limiting value<br />

Peql <strong>of</strong> this force that will initiate yielding on an extreme fibre will be given by<br />

which leads to<br />

where<br />

PE<br />

Peq1 i<br />

PE Peq1<br />

Pcro<br />

Peq1 ¼ Py<br />

Z þ Py<br />

PE<br />

Z ¼ iy<br />

r2 r ¼ radius <strong>of</strong> gyration<br />

y ¼ extreme compressive fibre distance<br />

A ¼ cross-sectional area<br />

Py ¼ squash load ¼ syA:<br />

1=2<br />

y<br />

¼ sy<br />

Ar2 Peql will obviously be greater than the strut strength Ps <strong>of</strong> a normal axially<br />

loaded strut with initial imperfections i. We can thus apply a reduction factor<br />

P s/P eql to evaluate P eq on the transverse stiffener, thus leading to

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!