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Hydraulic Design of Highway Culverts - DOT On-Line Publications

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. Example Problem #3 (English Units)<br />

Given:<br />

Q50 = 150 ft³/s<br />

ELhd = 96 ft<br />

Outlet Invert Elevation = 75 ft<br />

Approximate Culvert Length = 350 ft<br />

So = 0.05 ft/ft<br />

Shoulder Elevation = 102 ft<br />

The downstream channel approximates a 5-ft bottom width trapezoid with 2H:1V side slopes.<br />

The Manning’s n = 0.03<br />

Requirements:<br />

<strong>Design</strong> a culvert for the above conditions. Use corrugated metal pipe with standard (2-2/3 by 1/2<br />

in) corrugations. Investigate both a corrugated side-tapered inlet and a concrete slope-tapered<br />

inlet. Use normal depth in the natural channel as the tailwater depth.<br />

NOTE: Charts 4B, 6B, 55B, 56B, and 59B are used in this solution.<br />

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