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Introduction to Digital Signal and System Analysis - Tutorsindia

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<strong>Introduction</strong> <strong>to</strong> <strong>Digital</strong> <strong>Signal</strong> <strong>and</strong> <strong>System</strong> <strong>Analysis</strong><br />

Z Domain <strong>Analysis</strong><br />

where A, B, C are constants, which can be determined by the following steps.<br />

A B C<br />

X ( z)<br />

= + +<br />

z z −1<br />

2z<br />

−1<br />

A(<br />

z −1)(2<br />

z −1)<br />

+ Bz(2z<br />

−1)<br />

+ Cz(<br />

z −1)<br />

=<br />

z(<br />

z −1)(2<br />

z −1)<br />

A(2z<br />

=<br />

2<br />

2<br />

− 3z<br />

+ 1) + B(2z<br />

− z)<br />

+ C(<br />

z<br />

z(<br />

z −1)(2<br />

z −1)<br />

− z)<br />

2<br />

(2A<br />

+ 2B<br />

+ C)<br />

z + ( −3A<br />

− B − C)<br />

z + A<br />

=<br />

z(<br />

z −1)(2<br />

z −1)<br />

2<br />

i.e.<br />

2<br />

1 (2A<br />

+ 2B<br />

+ C)<br />

z + ( −3A<br />

− B − C)<br />

z + A<br />

=<br />

z(<br />

z −1)(2<br />

z −1)<br />

z(<br />

z −1)(2<br />

z −1)<br />

The numera<strong>to</strong>r of the left h<strong>and</strong> side is forced <strong>to</strong> equal <strong>to</strong> the right h<strong>and</strong> side, yielding the following simultaneous equations:<br />

⎧2A<br />

+ 2B<br />

+ C = 0<br />

⎪<br />

⎨ 3A<br />

+ B + C = 0<br />

⎪<br />

⎩ A = 1<br />

Solving the equations, the constants can be found as A=1, B=1, C=-4. Therefore,<br />

1<br />

X ( z)<br />

= +<br />

z<br />

1 4<br />

− = z<br />

z −1<br />

2z<br />

−1<br />

−1<br />

⎧<br />

⎨1<br />

+<br />

⎩<br />

z<br />

+<br />

z −1<br />

2z<br />

⎫<br />

⎬<br />

z − 0.5⎭<br />

.<br />

According <strong>to</strong> basic z-transform pair formulas in Table 5.2,<br />

1<br />

b<br />

d [ n]<br />

z<br />

z −1<br />

b<br />

u[<br />

n]<br />

2z<br />

z − 0.5<br />

b<br />

n<br />

2(0.5) u[<br />

n]<br />

Combining the time-shift fac<strong>to</strong>r<br />

−1<br />

z , the signal in time domain can be obtained as<br />

n−1<br />

x[<br />

n]<br />

= d [ n −1]<br />

+ u[<br />

n −1]<br />

− 2(0.5) u[<br />

n −1]<br />

.<br />

65<br />

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