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Introduction to Digital Signal and System Analysis - Tutorsindia

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<strong>Introduction</strong> <strong>to</strong> <strong>Digital</strong> <strong>Signal</strong> <strong>and</strong> <strong>System</strong> <strong>Analysis</strong><br />

Discrete Fourier Transform<br />

X [ k]<br />

=<br />

+ W<br />

k<br />

8<br />

<br />

s=<br />

0<br />

<br />

<br />

<br />

1<br />

1<br />

<br />

s=<br />

0<br />

x[2(2s)]<br />

W<br />

sk<br />

2<br />

x[2(2s)<br />

+ 1] W<br />

+ W<br />

sk<br />

2<br />

1<br />

k<br />

4 <br />

s=<br />

0<br />

+ W<br />

x[2(2s<br />

+ 1)] W<br />

1<br />

k<br />

4 <br />

s=<br />

0<br />

sk<br />

2<br />

x[2(2s<br />

+ 1) + 1] W<br />

sk<br />

2<br />

<br />

<br />

<br />

W k<br />

8<br />

W sk<br />

2<br />

2π<br />

k 2π<br />

k <br />

= exp<br />

− j , W k<br />

4 = exp<br />

− j <br />

8 4 <br />

2π<br />

sk <br />

= −<br />

0 1<br />

exp j , W<br />

2<br />

= 1, W2<br />

= −1<br />

2 <br />

Using the following graphical illustration in Figure 6.6, we can see the complex multiplications are only 4+6+7=17 in this<br />

case, much fewer than that in the direct calculation of the DFT.<br />

x[n]<br />

0<br />

<br />

0<br />

<br />

0<br />

⊕ ⊕<br />

X[k]<br />

0<br />

⊕<br />

1<br />

<br />

2<br />

<br />

4<br />

⊕ ⊕<br />

1<br />

⊕<br />

2<br />

<br />

4<br />

<br />

2<br />

⊕ ⊕<br />

2<br />

⊕<br />

3<br />

<br />

6<br />

<br />

6<br />

⊕ ⊕<br />

3<br />

⊕<br />

4<br />

<br />

1<br />

<br />

1<br />

⊕ ⊕<br />

4<br />

⊕<br />

5<br />

<br />

3<br />

<br />

5<br />

⊕ ⊕<br />

5<br />

⊕<br />

6<br />

<br />

5<br />

<br />

3<br />

⊕ ⊕<br />

6<br />

⊕<br />

7<br />

<br />

7<br />

<br />

7<br />

⊕ ⊕<br />

7<br />

⊕<br />

Figure 6.6 2 N=4 point DFT are changed <strong>to</strong> 4 N=2 point DFTs<br />

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98

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