Introduction to Digital Signal and System Analysis - Tutorsindia
Introduction to Digital Signal and System Analysis - Tutorsindia
Introduction to Digital Signal and System Analysis - Tutorsindia
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<strong>Introduction</strong> <strong>to</strong> <strong>Digital</strong> <strong>Signal</strong> <strong>and</strong> <strong>System</strong> <strong>Analysis</strong><br />
Z Domain <strong>Analysis</strong><br />
The z-plane is a complex plane in which the zeros <strong>and</strong> poles of a z-transform are plotted, which is used <strong>to</strong> visualise the<br />
properties of a signal or a system. The positions of the poles <strong>and</strong> zeros on a z-plane determine the frequency properties<br />
<strong>and</strong> degree of stability. On the other h<strong>and</strong>, in designing a digital system, the poles <strong>and</strong> zeros can be chosen <strong>to</strong> put in<br />
appropriate locations for achieving certain required performance.<br />
z-plane<br />
imaginary<br />
real<br />
Figure 5.3 z-plane<br />
Example 5.3: From the z -transform pair table, we Figure know the 5.3 unit z-plane step pair as<br />
z<br />
u[<br />
n]<br />
↔ z −1<br />
The z-transform of the unit step has one zero at origin as X ( z)<br />
= 0 <strong>and</strong> one pole z =1 as X z)<br />
→ ∞ , shown<br />
0<br />
in Figure 5.3 in which the pole is represented by a cross <strong>and</strong> the zero is represented by a circle.<br />
z=<br />
(<br />
z=1<br />
Example 5.4: Find zeros <strong>and</strong> poles for a z-transform<br />
2<br />
z ( z −1.2)(<br />
z + 1)<br />
X ( z)<br />
=<br />
.<br />
( z − 0.5 + j0.7)(<br />
z − 0.5 − j0.7)(<br />
z − 0.8)<br />
.<br />
Re-write it as<br />
X ( z)<br />
=<br />
( z − 0)( z − 0)( z −1.2)(<br />
z − ( −1))<br />
{ z − (0.5 − j0.7)<br />
}{ z − (0.5 + j0.7)<br />
}(<br />
z − 0.8)<br />
It can be obtained: 4 zeros: 0,0, 1.2, -1; <strong>and</strong> 3 poles: (0.5-j0.7), (0.5+j0.7), 0.8.<br />
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