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Introduction to Digital Signal and System Analysis - Tutorsindia

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<strong>Introduction</strong> <strong>to</strong> <strong>Digital</strong> <strong>Signal</strong> <strong>and</strong> <strong>System</strong> <strong>Analysis</strong><br />

Z Domain <strong>Analysis</strong><br />

The z-plane is a complex plane in which the zeros <strong>and</strong> poles of a z-transform are plotted, which is used <strong>to</strong> visualise the<br />

properties of a signal or a system. The positions of the poles <strong>and</strong> zeros on a z-plane determine the frequency properties<br />

<strong>and</strong> degree of stability. On the other h<strong>and</strong>, in designing a digital system, the poles <strong>and</strong> zeros can be chosen <strong>to</strong> put in<br />

appropriate locations for achieving certain required performance.<br />

z-plane<br />

imaginary<br />

real<br />

Figure 5.3 z-plane<br />

Example 5.3: From the z -transform pair table, we Figure know the 5.3 unit z-plane step pair as<br />

z<br />

u[<br />

n]<br />

↔ z −1<br />

The z-transform of the unit step has one zero at origin as X ( z)<br />

= 0 <strong>and</strong> one pole z =1 as X z)<br />

→ ∞ , shown<br />

0<br />

in Figure 5.3 in which the pole is represented by a cross <strong>and</strong> the zero is represented by a circle.<br />

z=<br />

(<br />

z=1<br />

Example 5.4: Find zeros <strong>and</strong> poles for a z-transform<br />

2<br />

z ( z −1.2)(<br />

z + 1)<br />

X ( z)<br />

=<br />

.<br />

( z − 0.5 + j0.7)(<br />

z − 0.5 − j0.7)(<br />

z − 0.8)<br />

.<br />

Re-write it as<br />

X ( z)<br />

=<br />

( z − 0)( z − 0)( z −1.2)(<br />

z − ( −1))<br />

{ z − (0.5 − j0.7)<br />

}{ z − (0.5 + j0.7)<br />

}(<br />

z − 0.8)<br />

It can be obtained: 4 zeros: 0,0, 1.2, -1; <strong>and</strong> 3 poles: (0.5-j0.7), (0.5+j0.7), 0.8.<br />

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