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Introduction to Digital Signal and System Analysis - Tutorsindia

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<strong>Introduction</strong> <strong>to</strong> <strong>Digital</strong> <strong>Signal</strong> <strong>and</strong> <strong>System</strong> <strong>Analysis</strong><br />

Discrete Fourier Transform<br />

6. Even <strong>and</strong> odd signals<br />

From the DFT definition<br />

N<br />

<br />

<br />

= − 1<br />

2πkn<br />

2πkn<br />

X [ k]<br />

x[<br />

n]<br />

cos<br />

− j sin <br />

n= 0 N N <br />

2πkn<br />

2πkn<br />

where cos is an even function, <strong>and</strong> sin is an odd function.<br />

N<br />

N<br />

Let<br />

Real( X[<br />

k])<br />

=<br />

Imag<br />

( X[<br />

k]<br />

)<br />

=<br />

N −1<br />

<br />

n=<br />

0<br />

N −1<br />

<br />

n=<br />

0<br />

2πkn<br />

x[<br />

n]cos<br />

N<br />

2πkn<br />

x[<br />

n]sin<br />

N<br />

When x[n] is real signal,<br />

a) if x[n] is an even function,<br />

Im(X[k]) =0 (6.9)<br />

b) if x[n] is an even function,<br />

Re(X[k]) =0 (6.10)<br />

This property can be used <strong>to</strong> simplify <strong>and</strong> save the calculation.<br />

7. Conjugation<br />

N<br />

1<br />

N<br />

1<br />

If x[n] is real, ∑ − X [0] = x[<br />

n]<br />

<strong>and</strong> ∑ − n<br />

X [ N / 2] = ( −1)<br />

x[<br />

n]<br />

are real coefficients, <strong>and</strong> the other N-2 are complex<br />

coefficients.<br />

n=<br />

0<br />

n=<br />

0<br />

X [ −k]<br />

=<br />

X * [ k]<br />

or<br />

X [ N − k]<br />

=<br />

X * [ k]<br />

(6.11)<br />

X [ −k]<br />

= X [ k]<br />

,<br />

X [ N − k]<br />

= X [ k]<br />

(6.12)<br />

Only X[0], X[N/2] <strong>and</strong> X(k), k=1,2,N/2-1 are needed <strong>to</strong> represent the whole X[k] (k=0,1,2,…,N-1). i.e. there are a <strong>to</strong>tal<br />

of 2 real <strong>and</strong> N/2-1 complex coefficients. It can also be proved<br />

92<br />

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