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Stochastic Programming - Index of

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RECOURSE PROBLEMS 179<br />

φ<br />

φ(ξ)<br />

ξ)<br />

1<br />

2<br />

ξ)<br />

ξ<br />

Figure 13<br />

Two possible lower bounding functions.<br />

oil from the second country gives 6 and 3 units <strong>of</strong> the same products. Company<br />

1 wants at least 180 + ξ 1 units <strong>of</strong> Product 1 and Company 2 at least 162 + ξ 2<br />

units <strong>of</strong> Product 2. The goal now is to find the expected value <strong>of</strong> φ(ξ); in other<br />

words, we seek the expected value <strong>of</strong> the “wait-and-see” solution. Note that<br />

this interpretation is not the one we adopted in Section 1.3.<br />

3.4.1 The Jensen Lower Bound<br />

Assume that q(ξ) ≡ q 0 , so that randomness affects only the right-hand side.<br />

The purpose <strong>of</strong> this section is to find a lower bound on Q(ˆx, ξ), for fixed ˆx,<br />

and for that purpose we shall, as just mentioned, use φ(ξ) ≡ Q(ˆx, ξ) fora<br />

fixed ˆx.<br />

Since φ(ξ) is a convex function, we can bound it from below by a linear<br />

function L(ξ) =cξ + d. Since the goal will always be to find a lower bound<br />

that is as large as possible, we shall require that the linear lower bound be<br />

tangent to φ(ξ) at some point ˆξ. Figure 13 shows two examples <strong>of</strong> such lowerbounding<br />

functions. But the question is which one should we pick. Is L 1 (ξ)<br />

or L 2 (ξ) the better<br />

If we let the lower bounding function L(ξ) be tangent to φ(ξ) atˆξ, theslope<br />

must be φ ′ (ˆξ), and we must have<br />

φ(ˆξ) =φ ′ (ˆξ)ˆξ + b,<br />

since φ(ˆξ) =L(ˆξ). Hence, in total, the lower-bounding function is given by<br />

L(ξ) =φ(ˆξ)+φ ′ (ˆξ)(ξ − ˆξ).<br />

Since this is a linear function, we easily calculate the expected value <strong>of</strong> the

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