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Stochastic Programming - Index of

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NETWORK PROBLEMS 305<br />

speaking, we are looking for the expected value <strong>of</strong> the objective function in<br />

(6.1) with respect to the random variables q(˜ξ). There is a very large collection<br />

<strong>of</strong> different methods for bounding PERT problems. Some papers are listed at<br />

the end <strong>of</strong> this chapter. However, most, if not all, <strong>of</strong> them can be categorized<br />

as belonging to one or more <strong>of</strong> the following groups.<br />

6.6.3.1 Series reductions<br />

If there is a node with only one incoming and one outgoing arc, the node is<br />

removed, and the arcs replaced by one arc with a duration equal to the sum<br />

<strong>of</strong> the two arc durations. This is an exact reformulation.<br />

6.6.3.2 Parallel reductions<br />

If two arcs run in parallel with durations ˜ξ 1 and ˜ξ 2 then they are replaced<br />

with one arc having duration max{˜ξ 1 , ˜ξ 2 }. This is also an exact reformulation.<br />

6.6.3.3 Disregarding path dependences<br />

Let ˜π i be a random variable describing when event i takes place. Then we can<br />

calculate<br />

˜π j =<br />

max {˜π i + q k (˜ξ)},<br />

i∈B + (i)\{i}<br />

with k ∼ (i, j),<br />

as if all these random variables were independent. However, in a PERT<br />

network, the ˜π’s will normally be dependent (even if the q’s are independent),<br />

since the paths leading up to the nodes usually share some arcs. Not only will<br />

they be dependent, but the correlation will always be positive, never negative.<br />

Hence viewing the random variables as independent will result in an upper<br />

bound on the project duration. The reason is that E max{˜ξ 1 , ˜ξ 2 } is smaller<br />

if the nonnegative ˜ξ 1 and ˜ξ 2 are (positively) correlated than if they are not<br />

correlated. A small example illustrates this<br />

Example 6.3 Assume we have two random variables ˜ξ 1 and ˜ξ 2 ,withjoint<br />

distribution as in Table 1. Note that both random variables have the same<br />

marginal distributions; namely, each <strong>of</strong> them can take on the values 1 or 2,<br />

each with a probability 0.5. Therefore E max{˜ξ 1 , ˜ξ 2 } =1.7 from Table 1, but<br />

0.25(1 + 2 + 2 + 2) = 1.75 if we use the marginal distributions as independent<br />

distributions. Therefore, if ˜ξ 1 and ˜ξ 2 represent two paths with some joint arc,<br />

disregarding the dependences will create an upper bound.<br />

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