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Stochastic Programming - Index of

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282 STOCHASTIC PROGRAMMING<br />

2<br />

1<br />

a<br />

b<br />

d<br />

f<br />

4 5<br />

g<br />

c<br />

3<br />

e<br />

Figure 3 Example network 1.<br />

least partially see the relevance <strong>of</strong> the last proposition. The following three<br />

inequalities are examples <strong>of</strong> inequalities describing feasibility for the example<br />

network:<br />

β(2) ≤ γ(d) + γ(f),<br />

β(3) ≤ γ(e),<br />

β(2) + β(3) ≤ γ(d) + γ(e) +γ(f).<br />

Proposition 6.2 states that the latter inequality is not needed, because<br />

G({2, 3}) is not connected. From the inequalities themselves, we easily see<br />

that if the first two are satisfied, then the third is automatically true. It is<br />

perhaps slightly less obvious that, for the very same reason, the inequality<br />

β(1) + β(4) + β(5) ≤ γ(a)+γ(c)<br />

is also not needed. It is implied by the requirement that total supply must<br />

equal total demand plus the companions <strong>of</strong> the first two inequalities above.<br />

(Remember that each node set gives rise to two inequalities). More specifically,<br />

the inequality can be obtained by adding the following two inequalities and<br />

one equality (representing supply equals demand):<br />

β(1) + β(2) + β(4) + β(5) ≤ γ(c),<br />

β(1) + β(3) + β(4) + β(5) ≤ γ(a),<br />

− β(1) − β(2) − β(3) − β(4) − β(5) = 0.<br />

✷<br />

Once you have looked at this for a while, you will probably realize that the<br />

part <strong>of</strong> Proposition 6.2 that says that if G(Y )orG(N \Y ) is disconnected

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