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Stochastic Programming - Index of

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18 STOCHASTIC PROGRAMMING<br />

✻<br />

%<br />

❜ 15<br />

<br />

❜<br />

<br />

❜<br />

❜<br />

❜ <br />

12<br />

9<br />

❜<br />

<br />

❜<br />

<br />

∼N(0, 12)<br />

❜ ∼N(0, 9)<br />

<br />

❜<br />

❜<br />

❜ <br />

3<br />

❜<br />

❜ <br />

❜<br />

❜ <br />

✲<br />

-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30<br />

Figure 7 Discrete distribution generated from N (0, 12), N (0, 9); (r 1,r 2)=<br />

(15, 15).<br />

6<br />

❜<br />

<br />

Obviously, these discrete distributions with 15 realizations each can<br />

only be rough approximations <strong>of</strong> the corresponding normal distributions.<br />

Therefore approximating probabilities <strong>of</strong> particular events using these discrete<br />

distributions can be expected to cause remarkable discretization errors. This<br />

will become evident in the following numerical examples.<br />

Using these latter distributions, with 15 realizations each, we get 15 2 =<br />

225 realizations for the joint distribution, and hence 225 blocks in our<br />

decomposition problem. This yields as an optimal solution for the linear<br />

program (3.11) (with γ(·) the total objective <strong>of</strong> (3.11) and γ I (x) =2x raw1 +<br />

3x raw2 )<br />

˜x =(˜x 1 , ˜x 2 )=(38.539, 20.539), γ(˜x) = 140.747, (3.12)<br />

with corresponding first-stage costs <strong>of</strong><br />

γ I (˜x) = 138.694.<br />

Defining ρ(x) as the empirical reliability (i.e. the probability to be feasible) for<br />

any production plan x, we find—with respect to the approximating discrete<br />

distribution—for our solution ˜x that<br />

ρ(˜x) =0.9541,<br />

whereas using our original linear program’s solution ˆx =(36, 18) would yield<br />

the total expected cost<br />

γ(ˆx) = 199.390

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