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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />
Section 1.1 • Assess Your Understanding 89 87<br />
In Problems (b) Investigate 13–16, use limtechnology cos π by using to complete a tablethe andtable evaluating and the In Problems (c) Graph 21–28, the function use the graph C. to investigate lim f (x). If the limit<br />
x→0 x2 x→c<br />
investigate the limit.<br />
function f (x) = cos π does<br />
x 2 at<br />
(d)<br />
not exist,<br />
Use the<br />
explain<br />
graph<br />
why.<br />
to investigate lim C(w) and lim C(w). Do<br />
w→1− w→1 +<br />
PAGE<br />
2 − 2e x<br />
82 13. lim x→0 x<br />
x =− 2 3 , − 2 5 , − 2 7 , − 2 9 ,..., 2 9 , 2 7 , 2 5 , 2 3 .<br />
21. these suggest that lim C(w) w→1 22. exists?<br />
y (e) Use the graph to investigate<br />
y<br />
x approaches 0 x approaches 0<br />
lim C(w) and lim C(w).<br />
w→12− w→12<br />
(c) Compare the resultsfrom the (a) left and (b). What from do youthe conclude right<br />
+<br />
about the limit? Why<br />
−−−−−−−−−−→<br />
do you think this happens?<br />
←−−−−−−−−−−<br />
Do these suggest that lim C(w) exists?<br />
What is your 3<br />
w→12 y f (x)<br />
viewx about using −0.2 a table −0.1to −0.01 draw a conclusion → 0 ← about 0.01limits?<br />
0.1 0.2<br />
y f (x)<br />
2<br />
(f) Use the graph to investigate lim C(w).<br />
w→0 +<br />
(d) f (x) Use = 2 technology − 2<br />
2ex<br />
1<br />
to graph f . Begin with the x-window<br />
1 (g) Use the graph to investigate lim<br />
x<br />
C(w).<br />
w→13<br />
[−2π, 2π] and the y-window [−1, 1]. If you were finding<br />
− (c, 1)<br />
(c, 1)<br />
lim ln xf (x) using a graph, what would you conclude? Zoom in<br />
c<br />
x<br />
61. Correlating c Student Success x to Study Time Professor Smith<br />
14. lim x→0<br />
x→1 on x −the 1 graph. Describe what you see. (Hint: Be sure your<br />
claims that a student’s final exam score is a function of the time t<br />
calculator is set to the radian mode.)<br />
(in hours) that the student studies. He claims that the closer to<br />
x approaches 1 x approaches 1<br />
PAGE<br />
x − 8<br />
23. seven hours one studies, the closer 24. to 100% the student scores<br />
85 57. (a) Use a table to investigate from the lim left . from the right y<br />
x→2 2<br />
on the final. He claims that studying y<br />
−−−−−−−−−−→ ←−−−−−−−−−−<br />
significantly less than seven<br />
(b) How x close must 0.9 x0.99 be to0.999 2, so that → f 1(x) ←is within 1.001 0.11.01 of the1.1<br />
hours may cause one to be underprepared for the test, while<br />
limit?<br />
studying significantly more than seven hours may cause<br />
(c) f (x) How =<br />
ln close x<br />
3 (c, 3) 3<br />
must x be to 2, so that f (x) is within 0.01 of the 2 “burnout.”<br />
2<br />
x − 1<br />
limit?<br />
y f (x)<br />
y f (x)<br />
1 (a) Write Professor Smith’s claim1<br />
symbolically as a limit.<br />
58. (a) Use a table to investigate lim(5 − 2x).<br />
PAGE<br />
1 − cos x<br />
(c, 1)<br />
x→2 (b) Write Professor Smith’s claim using the ε-δ definition<br />
82 15. lim , where x is measured in radians<br />
(b) x→0<br />
How<br />
x<br />
close must x be to 2, so that f (x) is within 0.1 of the<br />
ofclimit.<br />
x<br />
c<br />
x<br />
limit? x approaches 0 x approaches 0<br />
Source: Submitted by the students of Millikin University.<br />
(c) How close must x from be to 2, thesoleft<br />
that f (x) is within from the 0.01right<br />
of the<br />
PAGE<br />
limit? −−−−−−−−−−→ ←−−−−−−−−−− 84 25. 62. The definition of the slope of the26.<br />
tangent line to the graph of<br />
59. First-Class<br />
x (in radians)<br />
Mail<br />
−0.2<br />
As of<br />
−0.1<br />
April<br />
−0.01 → 0 ← 0.01 0.1 0.2<br />
y f (x) − f (c)<br />
y = f (x) at the point (c, f (c)) is m tan = lim<br />
.<br />
x→c<br />
2016, the U.S. Postal Service<br />
x − c<br />
f (x) = 1 − cos x<br />
y<br />
2<br />
charged $0.47 x postage for<br />
Another way y f to(x)<br />
express this slope 3is to define a new variable<br />
1<br />
first-class letters weighing up to<br />
h = x − c. Rewrite the slope of the tangent (c, 2) line my tan using f (x)<br />
sin x<br />
h and c.<br />
2<br />
16. and lim including , 1where ounce, xplus is measured a flat in radians<br />
x→0 1 + tan x<br />
63. If f (2) c = 6, can you conclude x anything about lim f (x)? Explain<br />
fee of $0.21 for each additional<br />
1<br />
x→2<br />
your reasoning.<br />
or partial ounce up to and x approaches 0 x approaches 0 2<br />
64. If lim f (x) = 6, can you conclude anything about f (2)? Explain<br />
including 3.5 ounces. First-class<br />
c<br />
x<br />
from the left from the right<br />
x→2<br />
letter rates do not apply−−−−−−−−−−→<br />
to letters<br />
←−−−−−−−−−− your reasoning.<br />
weighing x (in radians) more than−0.2 3.5 ounces. −0.1 −0.01 → 0 ← 0.01 0.1 0.2<br />
65. The graph of f (x) = x − 3 is a straight line with a point punched<br />
Source: U.S. Postal Service Notice 123<br />
3 − x<br />
f (x) =<br />
sin x<br />
27. 28.<br />
y out.<br />
y<br />
1 + tan x<br />
(a) Find a function C that models the first-class postage charged, (a) What straight line and what point?<br />
in dollars, for a letter weighing w ounces. Assume w>0. 3<br />
3<br />
In Problems 17–20, use the graph to investigate<br />
(b) Use the graph of f to investigate the one-sided limits of f as<br />
(a) lim<br />
(b) What<br />
f (x),<br />
is<br />
(b)<br />
the<br />
lim<br />
domain<br />
f (x),<br />
of<br />
(c)<br />
C?<br />
lim<br />
x approaches 3.<br />
(c) Graph the function C.<br />
f (x).<br />
(c, 2)<br />
y f (x)<br />
2<br />
y f (x)<br />
2 (c, 2)<br />
x→2− x→2 + x→2<br />
1 (c) Does the graph suggest that lim1<br />
f (x) exists? If so, what is it?<br />
(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />
x→3<br />
17. 18.<br />
w→2− w→2 +<br />
y<br />
y<br />
66. (a) Use c a table to investigate x lim(1 + x)<br />
these suggest that lim C(w) exists?<br />
1/x . c<br />
x<br />
x→0<br />
4<br />
w→2<br />
(e) Use the graph to investigate lim 4 C(w).<br />
(b) Use graphing technology to graph g(x) = (1 + x) 1/x .<br />
w→0 + (c) What do (a) and (b) suggest about lim(1 + x) 1/x ?<br />
(f) Use the graph to investigate lim C(w).<br />
x→0<br />
2 y f (x)<br />
w→3.5 2 − y f (x)<br />
CAS In Problems (d) Find29–36, lim(1 use + x) a 1/x graph . to investigate lim f (x) at the<br />
(2, 2)<br />
x→c x→0<br />
60. First-Class Mail As of April 2016, the U.S. Postal Service number c. <br />
charged $0.94 postage for first-class large envelope weighing up to<br />
2x + 5 if x ≤ 2<br />
2 4 x<br />
2 4 x 29. f (x) =<br />
at c = 2<br />
and including 1 ounce, plus a flat fee of $0.21 for each additional<br />
4x + 1 if x > 2<br />
or partial ounce up to and including 13 ounces. First-class rates do Challenge Problems 2x + 1 if x ≤ 0<br />
19. not apply to large envelopes weighing 20. more than 13 ounces. 30. For Problems f (x) = 67–70, investigate eachatof c = the0<br />
2x if x > 0 following limits.<br />
y<br />
Source: U.S. Postal Service Notice 123<br />
y<br />
⎧ { 1 if x is an integer<br />
6<br />
8<br />
⎨ 3x −f (x) 1 = if x < 1<br />
(a) (2, Find 6) a function C that models the first-class postage y charged, f (x) PAGE<br />
0 if x is not an integer<br />
in dollars, y for f a(x)<br />
large envelope6<br />
84 31. f (x) = 4 if x = 1 at c = 1<br />
weighing w ounces. Assume<br />
⎩<br />
4x if x > 1<br />
3 w>0.<br />
4<br />
67. lim f (x) 68. lim f (x) 69. lim f (x) 70. lim f (x)<br />
x→2 ⎧ x→1/2 x→3 x→0<br />
(b) What is the domain of C? 2<br />
⎨ x + 2 if x < 2<br />
32. f (x) = 4 if x = 2 at c = 2<br />
⎩<br />
2 4 x<br />
2 4 x<br />
x 2 if x > 2<br />
Kathryn Sidenstricker /Dreamstime.com<br />
− e<br />
13. lim 2 2 x<br />
=−2. For table values<br />
x→0<br />
x<br />
see TSM.<br />
x<br />
14. lim ln − =<br />
→ x 1 1 . For table values see<br />
x 1<br />
TSM.<br />
− x<br />
15. lim 1 cos = 0. For table values<br />
x→0<br />
x<br />
see TSM.<br />
x<br />
16. lim<br />
sin = 0. For table values<br />
x→0<br />
1+<br />
tanx<br />
see TSM.<br />
17. (a) 2<br />
(b) 2<br />
(c) 2<br />
18. (a) 4<br />
(b) 4<br />
(c) 4<br />
19. (a) 3<br />
(b) 6<br />
(c) Limit does not exist.<br />
20. (a) 4<br />
(b) 2<br />
(c) Limit does not exist.<br />
21. 1<br />
22. 1<br />
23. 1<br />
24. Limit does not exist.<br />
25. Limit does not exist, because the two<br />
one-sided limits are not equal.<br />
26. Limit does not exist.<br />
27. Limit does not exist, because the two<br />
one-sided limits are not equal.<br />
28. Limit does not exist.<br />
29. 9<br />
30. Limit does not exist.<br />
31. Limit does not exist.<br />
32. 4<br />
Section 1.1 • Assess Your Understanding<br />
87<br />
TE_<strong>Sullivan</strong>_Chapter01_PART 0.indd 16<br />
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