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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />

Section 1.1 • Assess Your Understanding 89 87<br />

In Problems (b) Investigate 13–16, use limtechnology cos π by using to complete a tablethe andtable evaluating and the In Problems (c) Graph 21–28, the function use the graph C. to investigate lim f (x). If the limit<br />

x→0 x2 x→c<br />

investigate the limit.<br />

function f (x) = cos π does<br />

x 2 at<br />

(d)<br />

not exist,<br />

Use the<br />

explain<br />

graph<br />

why.<br />

to investigate lim C(w) and lim C(w). Do<br />

w→1− w→1 +<br />

PAGE<br />

2 − 2e x<br />

82 13. lim x→0 x<br />

x =− 2 3 , − 2 5 , − 2 7 , − 2 9 ,..., 2 9 , 2 7 , 2 5 , 2 3 .<br />

21. these suggest that lim C(w) w→1 22. exists?<br />

y (e) Use the graph to investigate<br />

y<br />

x approaches 0 x approaches 0<br />

lim C(w) and lim C(w).<br />

w→12− w→12<br />

(c) Compare the resultsfrom the (a) left and (b). What from do youthe conclude right<br />

+<br />

about the limit? Why<br />

−−−−−−−−−−→<br />

do you think this happens?<br />

←−−−−−−−−−−<br />

Do these suggest that lim C(w) exists?<br />

What is your 3<br />

w→12 y f (x)<br />

viewx about using −0.2 a table −0.1to −0.01 draw a conclusion → 0 ← about 0.01limits?<br />

0.1 0.2<br />

y f (x)<br />

2<br />

(f) Use the graph to investigate lim C(w).<br />

w→0 +<br />

(d) f (x) Use = 2 technology − 2<br />

2ex<br />

1<br />

to graph f . Begin with the x-window<br />

1 (g) Use the graph to investigate lim<br />

x<br />

C(w).<br />

w→13<br />

[−2π, 2π] and the y-window [−1, 1]. If you were finding<br />

− (c, 1)<br />

(c, 1)<br />

lim ln xf (x) using a graph, what would you conclude? Zoom in<br />

c<br />

x<br />

61. Correlating c Student Success x to Study Time Professor Smith<br />

14. lim x→0<br />

x→1 on x −the 1 graph. Describe what you see. (Hint: Be sure your<br />

claims that a student’s final exam score is a function of the time t<br />

calculator is set to the radian mode.)<br />

(in hours) that the student studies. He claims that the closer to<br />

x approaches 1 x approaches 1<br />

PAGE<br />

x − 8<br />

23. seven hours one studies, the closer 24. to 100% the student scores<br />

85 57. (a) Use a table to investigate from the lim left . from the right y<br />

x→2 2<br />

on the final. He claims that studying y<br />

−−−−−−−−−−→ ←−−−−−−−−−−<br />

significantly less than seven<br />

(b) How x close must 0.9 x0.99 be to0.999 2, so that → f 1(x) ←is within 1.001 0.11.01 of the1.1<br />

hours may cause one to be underprepared for the test, while<br />

limit?<br />

studying significantly more than seven hours may cause<br />

(c) f (x) How =<br />

ln close x<br />

3 (c, 3) 3<br />

must x be to 2, so that f (x) is within 0.01 of the 2 “burnout.”<br />

2<br />

x − 1<br />

limit?<br />

y f (x)<br />

y f (x)<br />

1 (a) Write Professor Smith’s claim1<br />

symbolically as a limit.<br />

58. (a) Use a table to investigate lim(5 − 2x).<br />

PAGE<br />

1 − cos x<br />

(c, 1)<br />

x→2 (b) Write Professor Smith’s claim using the ε-δ definition<br />

82 15. lim , where x is measured in radians<br />

(b) x→0<br />

How<br />

x<br />

close must x be to 2, so that f (x) is within 0.1 of the<br />

ofclimit.<br />

x<br />

c<br />

x<br />

limit? x approaches 0 x approaches 0<br />

Source: Submitted by the students of Millikin University.<br />

(c) How close must x from be to 2, thesoleft<br />

that f (x) is within from the 0.01right<br />

of the<br />

PAGE<br />

limit? −−−−−−−−−−→ ←−−−−−−−−−− 84 25. 62. The definition of the slope of the26.<br />

tangent line to the graph of<br />

59. First-Class<br />

x (in radians)<br />

Mail<br />

−0.2<br />

As of<br />

−0.1<br />

April<br />

−0.01 → 0 ← 0.01 0.1 0.2<br />

y f (x) − f (c)<br />

y = f (x) at the point (c, f (c)) is m tan = lim<br />

.<br />

x→c<br />

2016, the U.S. Postal Service<br />

x − c<br />

f (x) = 1 − cos x<br />

y<br />

2<br />

charged $0.47 x postage for<br />

Another way y f to(x)<br />

express this slope 3is to define a new variable<br />

1<br />

first-class letters weighing up to<br />

h = x − c. Rewrite the slope of the tangent (c, 2) line my tan using f (x)<br />

sin x<br />

h and c.<br />

2<br />

16. and lim including , 1where ounce, xplus is measured a flat in radians<br />

x→0 1 + tan x<br />

63. If f (2) c = 6, can you conclude x anything about lim f (x)? Explain<br />

fee of $0.21 for each additional<br />

1<br />

x→2<br />

your reasoning.<br />

or partial ounce up to and x approaches 0 x approaches 0 2<br />

64. If lim f (x) = 6, can you conclude anything about f (2)? Explain<br />

including 3.5 ounces. First-class<br />

c<br />

x<br />

from the left from the right<br />

x→2<br />

letter rates do not apply−−−−−−−−−−→<br />

to letters<br />

←−−−−−−−−−− your reasoning.<br />

weighing x (in radians) more than−0.2 3.5 ounces. −0.1 −0.01 → 0 ← 0.01 0.1 0.2<br />

65. The graph of f (x) = x − 3 is a straight line with a point punched<br />

Source: U.S. Postal Service Notice 123<br />

3 − x<br />

f (x) =<br />

sin x<br />

27. 28.<br />

y out.<br />

y<br />

1 + tan x<br />

(a) Find a function C that models the first-class postage charged, (a) What straight line and what point?<br />

in dollars, for a letter weighing w ounces. Assume w>0. 3<br />

3<br />

In Problems 17–20, use the graph to investigate<br />

(b) Use the graph of f to investigate the one-sided limits of f as<br />

(a) lim<br />

(b) What<br />

f (x),<br />

is<br />

(b)<br />

the<br />

lim<br />

domain<br />

f (x),<br />

of<br />

(c)<br />

C?<br />

lim<br />

x approaches 3.<br />

(c) Graph the function C.<br />

f (x).<br />

(c, 2)<br />

y f (x)<br />

2<br />

y f (x)<br />

2 (c, 2)<br />

x→2− x→2 + x→2<br />

1 (c) Does the graph suggest that lim1<br />

f (x) exists? If so, what is it?<br />

(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />

x→3<br />

17. 18.<br />

w→2− w→2 +<br />

y<br />

y<br />

66. (a) Use c a table to investigate x lim(1 + x)<br />

these suggest that lim C(w) exists?<br />

1/x . c<br />

x<br />

x→0<br />

4<br />

w→2<br />

(e) Use the graph to investigate lim 4 C(w).<br />

(b) Use graphing technology to graph g(x) = (1 + x) 1/x .<br />

w→0 + (c) What do (a) and (b) suggest about lim(1 + x) 1/x ?<br />

(f) Use the graph to investigate lim C(w).<br />

x→0<br />

2 y f (x)<br />

w→3.5 2 − y f (x)<br />

CAS In Problems (d) Find29–36, lim(1 use + x) a 1/x graph . to investigate lim f (x) at the<br />

(2, 2)<br />

x→c x→0<br />

60. First-Class Mail As of April 2016, the U.S. Postal Service number c. <br />

charged $0.94 postage for first-class large envelope weighing up to<br />

2x + 5 if x ≤ 2<br />

2 4 x<br />

2 4 x 29. f (x) =<br />

at c = 2<br />

and including 1 ounce, plus a flat fee of $0.21 for each additional<br />

4x + 1 if x > 2<br />

or partial ounce up to and including 13 ounces. First-class rates do Challenge Problems 2x + 1 if x ≤ 0<br />

19. not apply to large envelopes weighing 20. more than 13 ounces. 30. For Problems f (x) = 67–70, investigate eachatof c = the0<br />

2x if x > 0 following limits.<br />

y<br />

Source: U.S. Postal Service Notice 123<br />

y<br />

⎧ { 1 if x is an integer<br />

6<br />

8<br />

⎨ 3x −f (x) 1 = if x < 1<br />

(a) (2, Find 6) a function C that models the first-class postage y charged, f (x) PAGE<br />

0 if x is not an integer<br />

in dollars, y for f a(x)<br />

large envelope6<br />

84 31. f (x) = 4 if x = 1 at c = 1<br />

weighing w ounces. Assume<br />

⎩<br />

4x if x > 1<br />

3 w>0.<br />

4<br />

67. lim f (x) 68. lim f (x) 69. lim f (x) 70. lim f (x)<br />

x→2 ⎧ x→1/2 x→3 x→0<br />

(b) What is the domain of C? 2<br />

⎨ x + 2 if x < 2<br />

32. f (x) = 4 if x = 2 at c = 2<br />

⎩<br />

2 4 x<br />

2 4 x<br />

x 2 if x > 2<br />

Kathryn Sidenstricker /Dreamstime.com<br />

− e<br />

13. lim 2 2 x<br />

=−2. For table values<br />

x→0<br />

x<br />

see TSM.<br />

x<br />

14. lim ln − =<br />

→ x 1 1 . For table values see<br />

x 1<br />

TSM.<br />

− x<br />

15. lim 1 cos = 0. For table values<br />

x→0<br />

x<br />

see TSM.<br />

x<br />

16. lim<br />

sin = 0. For table values<br />

x→0<br />

1+<br />

tanx<br />

see TSM.<br />

17. (a) 2<br />

(b) 2<br />

(c) 2<br />

18. (a) 4<br />

(b) 4<br />

(c) 4<br />

19. (a) 3<br />

(b) 6<br />

(c) Limit does not exist.<br />

20. (a) 4<br />

(b) 2<br />

(c) Limit does not exist.<br />

21. 1<br />

22. 1<br />

23. 1<br />

24. Limit does not exist.<br />

25. Limit does not exist, because the two<br />

one-sided limits are not equal.<br />

26. Limit does not exist.<br />

27. Limit does not exist, because the two<br />

one-sided limits are not equal.<br />

28. Limit does not exist.<br />

29. 9<br />

30. Limit does not exist.<br />

31. Limit does not exist.<br />

32. 4<br />

Section 1.1 • Assess Your Understanding<br />

87<br />

TE_<strong>Sullivan</strong>_Chapter01_PART 0.indd 16<br />

11/01/17 9:52 am

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