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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />

<strong>Sullivan</strong><br />

100 Chapter 1 • Limits and Continuity<br />

8. 2<br />

9. False<br />

10. True<br />

11. 14<br />

12. –3<br />

13. 0<br />

14. 18<br />

15. 1<br />

16. 1<br />

17. 6<br />

18. 1 2<br />

19. 11<br />

20. 10<br />

21. 2 78<br />

22. 0<br />

23. 7+<br />

3<br />

24. 2<br />

25. 0<br />

26. 0<br />

27. 5<br />

28. 1<br />

29. − 31<br />

8<br />

30. –3<br />

31. 10<br />

32. 14 3<br />

33. 13 4<br />

34. 1 5<br />

35. 4<br />

8. If the domain of a rational function R is {x | x = 0},<br />

then lim R(x) = R( ).<br />

x→2<br />

9. True or False Properties of limits cannot be used for one-sided<br />

limits.<br />

(x + 1)(x + 2)<br />

10. True or False If f (x) = and g(x) = x + 2,<br />

x + 1<br />

then lim f (x) = lim g(x).<br />

x→−1 x→−1<br />

Skill Building<br />

In Problems 11–44, find each limit using properties of limits.<br />

11. lim [2(x + 4)] 12. lim [3(x + 1)]<br />

x→3 x→−2<br />

PAGE<br />

93 13. lim [x(3x−1)(x + 2)]<br />

x→−2<br />

14. lim [x(x − 1)(x + 10)]<br />

x→−1<br />

PAGE<br />

94 15. lim (3t − 2) 3<br />

t→1<br />

16. lim (−3x + 1) 2<br />

x→0<br />

17. lim (3 √ ( ) 1<br />

x) 18. lim<br />

3√ x x→4 x→8 4<br />

√<br />

PAGE<br />

95 19. lim 5x − 4<br />

x→3<br />

20. lim<br />

t→2<br />

√<br />

3t + 4<br />

21. lim t→2<br />

[t √ (5t + 3)(t + 4)] 22. lim<br />

t→−1 [t 3√ (t + 1)(2t − 1)]<br />

PAGE<br />

95 23. lim ( √ x + x + 4) 1/2<br />

x→3<br />

24. lim t→2<br />

(t √ 2t + 4) 1/3<br />

25. lim<br />

t→−1 [4t(t + 1)]2/3 26. lim x→0<br />

(x 2 − 2x) 3/5<br />

27. lim t→1<br />

(3t 2 − 2t + 4) 28. lim x→0<br />

(−3x 4 + 2x + 1)<br />

PAGE<br />

96 29. lim (2x 4 − 8x 3 + 4x − 5) 30. lim (27x 3 + 9x + 1)<br />

x→ 1 2<br />

x→− 1 3<br />

PAGE<br />

97 31.<br />

x 2 + 4<br />

lim √ x→4 x<br />

32.<br />

x 2 + 5<br />

lim √ x→3 3x<br />

PAGE<br />

97 33.<br />

2x 3 + 5x<br />

lim<br />

x→−2 3x − 2<br />

PAGE<br />

97 35.<br />

x 2 − 4<br />

lim x→2 x − 2<br />

x 3 − x<br />

37. lim<br />

x→−1 x + 1<br />

39. lim<br />

x→−8<br />

( 2x<br />

x + 8 + 16<br />

x + 8<br />

√ √<br />

PAGE<br />

x − 2<br />

98 41. lim x→2 x − 2<br />

43. lim x→4<br />

√<br />

x + 5 − 3<br />

(x − 4)(x + 1)<br />

)<br />

34. lim x→1<br />

2x 4 − 1<br />

3x 3 + 2<br />

x + 2<br />

36. lim<br />

x→−2 x 2 − 4<br />

x 3 + x 2<br />

38. lim<br />

x→−1 x 2 − 1<br />

40. lim x→2<br />

( 3x<br />

x − 2 − 6<br />

x − 2<br />

42. lim x→3<br />

√ x −<br />

√<br />

3<br />

x − 3<br />

44. lim x→3<br />

√<br />

x + 1 − 2<br />

x(x − 3)<br />

In Problems 45–50, find each one-sided limit using properties of limits.<br />

45. lim<br />

x→3 −(x2 − 4) 46. lim<br />

x→2 +(3x2 + x)<br />

x 2 − 9<br />

47. lim<br />

x→3 − x − 3<br />

x 2 − 9<br />

48. lim<br />

x→3 + x − 3<br />

√<br />

√<br />

49. lim<br />

x→3 −( 9 − x 2 + x) 2 50. lim<br />

x→2 +(2 x 2 − 4 + 3x)<br />

)<br />

In Problems 51–58, use the information below to find each limit.<br />

lim f (x) = 5<br />

x→c<br />

lim g(x) = 2<br />

x→c<br />

lim h(x) = 0<br />

x→c<br />

51. lim x→c<br />

[ f (x) − 3g(x)] 52. lim x→c<br />

[5 f (x)]<br />

53. lim [g(x)] 3 f (x)<br />

54. lim<br />

x→c x→c g(x) − h(x)<br />

55. lim x→c<br />

h(x)<br />

g(x)<br />

[ 1<br />

57. lim x→c g(x)<br />

56. lim x→c<br />

[4 f (x) · g(x)]<br />

] 2<br />

58. lim x→c<br />

3 √ 5g(x) − 3<br />

In Problems 59 and 60, use the graphs of the functions and properties<br />

of limits to find each limit, if it exists. If the limit does not exist, write,<br />

“the limit does not exist,” and explain why.<br />

59. (a) lim [ f (x) + g(x)]<br />

x→4<br />

y<br />

y h(x)<br />

10 y f (x)<br />

(b) lim { f (x) [g(x) − h(x)]}<br />

x→4 8<br />

(c) lim[ f (x) · g(x)]<br />

x→4 6<br />

(4, 6)<br />

(d) lim[2h(x)]<br />

x→4<br />

g(x)<br />

2<br />

(e) lim x→4 f (x)<br />

(4, 0)<br />

(f)<br />

8 x<br />

h(x)<br />

2<br />

lim<br />

y g(x)<br />

x→4<br />

(3, 2)<br />

f (x)<br />

60. (a) lim x→3<br />

{2 [ f (x) + h(x)]}<br />

(b)<br />

lim + h(x)]<br />

x→3−[g(x) (c) lim x→3<br />

3 √ h(x)<br />

(d) lim x→3<br />

f (x)<br />

h(x)<br />

(e) lim x→3<br />

[h(x)] 3<br />

(f)<br />

lim[ f (x) − 2h(x)] 3/2<br />

x→3<br />

y<br />

6<br />

4<br />

2<br />

2<br />

y f (x)<br />

(3, 2)<br />

y g(x)<br />

3<br />

(3, 6)<br />

y h(x)<br />

In Problems 61–66, for each function f, find the limit as x approaches c<br />

of the average rate of change of f from c to x. That is, find<br />

f (x) − f (c)<br />

lim<br />

x→c x − c<br />

61. f (x) = 3x 2 , c = 1 62. f (x) = 8x 3 , c = 2<br />

PAGE<br />

98 63. f (x) =−2x 2 + 4, c = 1 64. f (x) = 20 − 0.8x 2 , c = 3<br />

65. f (x) = √ x, c = 1 66. f (x) = √ 2x, c = 5<br />

In Problems 67–72, find the limit of the difference quotient for each<br />

f (x + h) − f (x)<br />

function f . That is, find lim<br />

.<br />

h→0 h<br />

67. f (x) = 4x − 3 68. f (x) = 3x + 5<br />

69. f (x) = 3x 2 + 4x + 1 70. f (x) = 2x 2 + x<br />

PAGE<br />

99 71. f (x) = 2 x<br />

72. f (x) = 3 x 2<br />

x<br />

36. − 1 4<br />

37. 2<br />

38. − 1 2<br />

39. 2<br />

40. 3<br />

2<br />

41.<br />

4<br />

3<br />

42.<br />

6<br />

1<br />

43.<br />

30<br />

1<br />

44.<br />

12<br />

45. 5<br />

46. 14<br />

47. 6<br />

48. 6<br />

49. 9<br />

50. 6<br />

51. –1<br />

52. 25<br />

53. 8<br />

54. 5 2<br />

55. 0<br />

56. 40<br />

57. 1 4<br />

3<br />

58. 7<br />

59. (a) 6<br />

(b) –16<br />

(c) –16<br />

(d) 0<br />

(e) − 1 4<br />

(f) 0<br />

60. (a) –4<br />

(b) 4<br />

3<br />

(c) − 2<br />

(d) 0<br />

(e) –8<br />

(f) 8<br />

61. 6<br />

62. 96<br />

63. –4<br />

64. –4.8<br />

65. 1 2<br />

1<br />

66.<br />

10<br />

67. 4<br />

68. 3<br />

69. 6x + 4<br />

70. 4x + 1<br />

2<br />

71. −<br />

x<br />

2<br />

6<br />

72. −<br />

x<br />

3<br />

100<br />

Chapter 1 • Limits and Continuity<br />

TE_<strong>Sullivan</strong>_Chapter01_PART 0.indd 29<br />

11/01/17 9:53 am

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