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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />

Section 1.2 • Limits Section of Functions 1.1 • Assess UsingYour Properties Understanding of Limits 89 97<br />

(b) Investigate lim cos π by using a table and evaluating the<br />

x→0 x2 EXAMPLE 11 Finding(c) theGraph Limit theofunction a Rational C. Function<br />

function f (x) = cos π x 2 at<br />

Find:<br />

(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />

w→1− w→1 +<br />

x =− 2 3 , − 2 5 , − 2 7 , − 2 9 ,..., 2 9 , 2 7 , 2 5 , 2 3x 3 − 2x + 1 these suggest that 2x + lim<br />

3 .<br />

w→1<br />

4 C(w) exists?<br />

(a) lim<br />

(b) lim<br />

x→1 4x 2 + 5 (e) Use thex→−2<br />

graph3x to 2 investigate − 1 lim C(w) and lim C(w).<br />

w→12− w→12<br />

(c) Compare the results from (a) and (b). What do you conclude<br />

+<br />

about the limit? Why do you think this happens? Solution What (a) isSince your 1 is in the domain<br />

Do these<br />

of<br />

suggest<br />

the rational<br />

that lim<br />

w→12 function<br />

C(w) exists?<br />

R(x) = 3x 3 − 2x + 1<br />

,<br />

view about using a table to draw a conclusion about limits? (f) Use the graph to investigate lim C(w). 4x 2 + 5<br />

w→0<br />

lim<br />

+<br />

(d) Use technology to graph f . Begin with the x-window<br />

(g) R(x) Use = R(1) = 3 − 2 + 1 = 2<br />

x→1 ↑the graph to investigate 4 + 5 lim9<br />

C(w).<br />

w→13<br />

[−2π, 2π] and the y-window [−1, 1]. If you were finding<br />

− Use (3)<br />

lim f (x) using a graph, what would you conclude? Zoom in 61. Correlating Student Success to Study Time Professor Smith<br />

x→0<br />

on the graph. Describe what you see. (Hint: (b) Be Since sure −2 youris in the domain claims of the thatrational a student’s function final exam H(x) score = is 2x a function + 4 of the time t<br />

calculator is set to the radian mode.)<br />

(in hours) that the student studies. He claims 3x 2 −that 1 ,<br />

the closer to<br />

PAGE<br />

x − 8<br />

seven hours one studies, the closer to 100% the student scores<br />

85 57. (a) Use a table to investigate lim .<br />

lim<br />

x→2 2<br />

on H(x) the = H(−2) = −4 + 4<br />

x→−2 ↑final. He claims12that − studying 1 = 0<br />

11 significantly = 0 less than seven<br />

■<br />

(b) How close must x be to 2, so that f (x) is within 0.1 of the hours Use may (3) cause one to be underprepared for the test, while<br />

limit?<br />

studying significantly more than seven hours may cause<br />

(c) How close must x be to 2, so that f (x) is within 0.01 of the “burnout.”<br />

NOW WORK Problem 33.<br />

limit?<br />

(a) Write Professor Smith’s claim symbolically as a limit.<br />

58. (a) Use a table to investigate lim(5 − 2x).<br />

x→2<br />

EXAMPLE 12 Finding(b) theWrite Limit Professor a Quotient Smith’s claim using the ε-δ definition<br />

√<br />

(b) How close must x be to 2, so that f (x) is within 0.1 of the<br />

of limit.<br />

3x 2<br />

+ 1<br />

limit?<br />

Find lim .<br />

x→4 x − 1 Source: Submitted by the students of Millikin University.<br />

(c) How close must x be to 2, so that f (x) is within 0.01 of the<br />

62. The definition of the slope of the tangent line to graph of<br />

limit?<br />

Solution We seek the limit of the quotient of two functions. Since the limit of the<br />

f (x) − f (c)<br />

59. First-Class Mail As of April<br />

denominator lim(x − 1) = 0, we use the Limit of a Quotient.<br />

x→4 y = f (x) at the point (c, f (c)) is m tan = lim<br />

.<br />

x→c<br />

2016, the U.S. Postal Service<br />

x − c<br />

√<br />

√ √<br />

charged $0.47 postage for<br />

3x 2<br />

+ 1<br />

lim 3x Another 2<br />

+ 1way to express lim (3x 2 √<br />

this + slope 1)<br />

√<br />

is to define a new variable<br />

x→4<br />

x→4 3 · 42 + 1 49<br />

first-class letters weighing up to<br />

lim = h = x − c. Rewrite the slope of the tangent line m tan using h and c.<br />

x→4 x − 1 lim<br />

and including 1 ounce, plus a flat<br />

63. (x If − f (2) 1) =<br />

lim<br />

= 6, can you (x conclude − 1) =<br />

= = 7 4 − 1 3 3<br />

↑ x→4 ↑ x→4 anything about lim f (x)? Explain<br />

fee of $0.21 for each additional<br />

Limit of a Quotient<br />

x→2<br />

your<br />

Limit<br />

reasoning.<br />

of a Root<br />

■<br />

or partial ounce up to and<br />

64. If lim f (x) = 6, can you conclude anything NOW WORK about f (2)? Problem Explain 31.<br />

including 3.5 ounces. First-class<br />

x→2<br />

letter rates do not apply to letters<br />

Based on these examples, your you reasoning. might be tempted<br />

weighing more than 3.5 ounces.<br />

65. The graph of f (x) = x − 3 to conclude that finding a limit as x<br />

approaches c is simply a matter of substituting the number is a straight c intoline thewith function. a pointThe punched next<br />

Source: U.S. Postal Service Notice 123 few examples show that substitution<br />

3 − x<br />

out. cannot always be used and other strategies need to<br />

be employed.<br />

(a) Find a function C that models the first-class postage charged, (a) What straight line and what point?<br />

in dollars, for a letter weighing w ounces. Assume The w>0. limit of a rational function can be found using substitution, provided the<br />

(b) Use the graph of f to investigate the one-sided limits of f as<br />

(b) What is the domain of C?<br />

number c being approached is in the domain of the rational function. The next example<br />

x approaches 3.<br />

(c) Graph the function C.<br />

shows a strategy that can be tried when c is not in the domain.<br />

(c) Does the graph suggest that lim f (x) exists? If so, what is it?<br />

(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />

x→3<br />

w→2− w→2 +<br />

66. (a) Use a table to investigate lim(1 + x)<br />

these suggest that lim C(w) exists? EXAMPLE 13 Finding the Limit of a Rational 1/x .<br />

x→0<br />

Function<br />

w→2<br />

(e) Use the graph to investigate lim<br />

x 2 + 5x + 6 (b) Use graphing technology to graph g(x) = (1 + x) 1/x .<br />

.<br />

x 2 − 4 (c) What do (a) and (b) suggest about lim<br />

Kathryn Sidenstricker /Dreamstime.com<br />

C(w).<br />

w→0 + Find lim<br />

(f) Use the graph to investigate lim C(w).<br />

x→−2<br />

(1 + x) 1/x ?<br />

x→0<br />

w→3.5 − Solution Since −2 is not CAS in(d) theFind domain lim(1 of+ the x) 1/x rational . function, substitution cannot be<br />

60. First-Class Mail As of April 2016, the U.S. used. Postal But Service this does not mean that the x→0<br />

limit does not exist! Factoring the numerator and<br />

charged $0.94 postage for first-class large envelope the denominator, weighing up to we find<br />

and including 1 ounce, plus a flat fee of $0.21 for each additional<br />

or partial ounce up to and including 13 ounces. First-class rates do Challenge x 2 + 5x Problems + 6 (x + 2)(x + 3)<br />

=<br />

not apply to large envelopes weighing more than 13 ounces.<br />

x<br />

For Problems 2 − 4 (x + 2)(x − 2)<br />

67–70, investigate each of the following limits.<br />

Source: U.S. Postal Service Notice 123 Since x = −2, and we are interested in the limit<br />

{<br />

as 1 x approaches if x is an integer −2, the factor x + 2<br />

f (x) =<br />

(a) Find a function C that models the first-class canpostage be divided charged, out. Then<br />

0 if x is not an integer<br />

in dollars, for a large envelope weighing w ounces. Assume x 2 + 5x + 6 (x + 2)(x + 3)<br />

w>0.<br />

lim<br />

67. = lim<br />

f (x) 68. lim f (x) 69. lim f (x) 70. lim f (x)<br />

x→−2 x 2 − 4 x→−2 x→2 (x + 2)(x −x→1/2 2) = lim x + 3<br />

x→−2 x − 2 = −2 + 3<br />

↑<br />

↑<br />

x→3<br />

↑ −2 − 2 =−1 x→0 4<br />

(b) What is the domain of C?<br />

Factor<br />

x = −2<br />

Divide out ( x + 2)<br />

Use the Limit of a<br />

Rational Function<br />

NOW WORK Problem 35 and AP® Practice Problem 2.<br />

■<br />

AP® Calc Skill Builder<br />

for Example 11<br />

Finding the Limit of a Rational Function<br />

3<br />

x − 9x<br />

Find lim<br />

→ x − 3 .<br />

x 3<br />

Solution<br />

3<br />

x 9x<br />

x x<br />

lim lim ( 2<br />

−<br />

−<br />

=<br />

9)<br />

x→3<br />

x − 3 x→3<br />

x − 3<br />

x( x− 3)( x + 3)<br />

= lim<br />

x→3<br />

x − 3<br />

= lim x( x+ 3) = 3(3+ 3) = 18<br />

x→3<br />

To reinforce notational fluency, remind<br />

students that the limit notation must be<br />

included in each step of the factorization.<br />

Also, encourage them to proceed gradually,<br />

step by step, when factoring expressions.<br />

For your visual learners, use the graph of<br />

the function to explain this limit.<br />

24<br />

22<br />

y<br />

18<br />

15<br />

12<br />

9<br />

6<br />

3<br />

Alternate Example<br />

Finding the Limit of a Rational Function<br />

x − x<br />

Find lim 9 3/2 7/2<br />

.<br />

→ + 5/2 3/2<br />

x 0 x − 3x<br />

Solution<br />

Factor numerator and denominator:<br />

x − x<br />

lim 9<br />

→0<br />

x − 3x<br />

x<br />

3/2 7/2<br />

=<br />

lim<br />

+ 5/2 3/2 +<br />

x→0<br />

x<br />

x<br />

2<br />

4<br />

x<br />

(9 − x )<br />

( x−<br />

3)<br />

3/2 2<br />

3/2<br />

TRM Section 1.2: Worksheet 2<br />

In this two-page worksheet, graphs are provided<br />

for 6 limit questions that each require some<br />

form of algebraic manipulation. An additional 6<br />

questions cover the properties of limits given a<br />

table of values.<br />

TRM Section 1.2: Worksheet 3<br />

This worksheet contains 8 limit questions that can<br />

be solved using techniques learned in this section.<br />

Graphs are not provided for answer verification.<br />

=<br />

−x<br />

lim<br />

x<br />

+<br />

x→0<br />

( x −9)<br />

( x−<br />

3)<br />

( x− 3)( x+<br />

3)<br />

=−lim +<br />

x→0<br />

( x − 3)<br />

=− lim ( x + 3) =−3<br />

+<br />

x→0<br />

3/2 2<br />

3/2<br />

Section 1.2 • Limits of Functions Using Properties of Limits<br />

97<br />

TE_<strong>Sullivan</strong>_Chapter01_PART 0.indd 26<br />

11/01/17 9:52 am

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