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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />
Section 1.2 • Limits Section of Functions 1.1 • Assess UsingYour Properties Understanding of Limits 89 97<br />
(b) Investigate lim cos π by using a table and evaluating the<br />
x→0 x2 EXAMPLE 11 Finding(c) theGraph Limit theofunction a Rational C. Function<br />
function f (x) = cos π x 2 at<br />
Find:<br />
(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />
w→1− w→1 +<br />
x =− 2 3 , − 2 5 , − 2 7 , − 2 9 ,..., 2 9 , 2 7 , 2 5 , 2 3x 3 − 2x + 1 these suggest that 2x + lim<br />
3 .<br />
w→1<br />
4 C(w) exists?<br />
(a) lim<br />
(b) lim<br />
x→1 4x 2 + 5 (e) Use thex→−2<br />
graph3x to 2 investigate − 1 lim C(w) and lim C(w).<br />
w→12− w→12<br />
(c) Compare the results from (a) and (b). What do you conclude<br />
+<br />
about the limit? Why do you think this happens? Solution What (a) isSince your 1 is in the domain<br />
Do these<br />
of<br />
suggest<br />
the rational<br />
that lim<br />
w→12 function<br />
C(w) exists?<br />
R(x) = 3x 3 − 2x + 1<br />
,<br />
view about using a table to draw a conclusion about limits? (f) Use the graph to investigate lim C(w). 4x 2 + 5<br />
w→0<br />
lim<br />
+<br />
(d) Use technology to graph f . Begin with the x-window<br />
(g) R(x) Use = R(1) = 3 − 2 + 1 = 2<br />
x→1 ↑the graph to investigate 4 + 5 lim9<br />
C(w).<br />
w→13<br />
[−2π, 2π] and the y-window [−1, 1]. If you were finding<br />
− Use (3)<br />
lim f (x) using a graph, what would you conclude? Zoom in 61. Correlating Student Success to Study Time Professor Smith<br />
x→0<br />
on the graph. Describe what you see. (Hint: (b) Be Since sure −2 youris in the domain claims of the thatrational a student’s function final exam H(x) score = is 2x a function + 4 of the time t<br />
calculator is set to the radian mode.)<br />
(in hours) that the student studies. He claims 3x 2 −that 1 ,<br />
the closer to<br />
PAGE<br />
x − 8<br />
seven hours one studies, the closer to 100% the student scores<br />
85 57. (a) Use a table to investigate lim .<br />
lim<br />
x→2 2<br />
on H(x) the = H(−2) = −4 + 4<br />
x→−2 ↑final. He claims12that − studying 1 = 0<br />
11 significantly = 0 less than seven<br />
■<br />
(b) How close must x be to 2, so that f (x) is within 0.1 of the hours Use may (3) cause one to be underprepared for the test, while<br />
limit?<br />
studying significantly more than seven hours may cause<br />
(c) How close must x be to 2, so that f (x) is within 0.01 of the “burnout.”<br />
NOW WORK Problem 33.<br />
limit?<br />
(a) Write Professor Smith’s claim symbolically as a limit.<br />
58. (a) Use a table to investigate lim(5 − 2x).<br />
x→2<br />
EXAMPLE 12 Finding(b) theWrite Limit Professor a Quotient Smith’s claim using the ε-δ definition<br />
√<br />
(b) How close must x be to 2, so that f (x) is within 0.1 of the<br />
of limit.<br />
3x 2<br />
+ 1<br />
limit?<br />
Find lim .<br />
x→4 x − 1 Source: Submitted by the students of Millikin University.<br />
(c) How close must x be to 2, so that f (x) is within 0.01 of the<br />
62. The definition of the slope of the tangent line to graph of<br />
limit?<br />
Solution We seek the limit of the quotient of two functions. Since the limit of the<br />
f (x) − f (c)<br />
59. First-Class Mail As of April<br />
denominator lim(x − 1) = 0, we use the Limit of a Quotient.<br />
x→4 y = f (x) at the point (c, f (c)) is m tan = lim<br />
.<br />
x→c<br />
2016, the U.S. Postal Service<br />
x − c<br />
√<br />
√ √<br />
charged $0.47 postage for<br />
3x 2<br />
+ 1<br />
lim 3x Another 2<br />
+ 1way to express lim (3x 2 √<br />
this + slope 1)<br />
√<br />
is to define a new variable<br />
x→4<br />
x→4 3 · 42 + 1 49<br />
first-class letters weighing up to<br />
lim = h = x − c. Rewrite the slope of the tangent line m tan using h and c.<br />
x→4 x − 1 lim<br />
and including 1 ounce, plus a flat<br />
63. (x If − f (2) 1) =<br />
lim<br />
= 6, can you (x conclude − 1) =<br />
= = 7 4 − 1 3 3<br />
↑ x→4 ↑ x→4 anything about lim f (x)? Explain<br />
fee of $0.21 for each additional<br />
Limit of a Quotient<br />
x→2<br />
your<br />
Limit<br />
reasoning.<br />
of a Root<br />
■<br />
or partial ounce up to and<br />
64. If lim f (x) = 6, can you conclude anything NOW WORK about f (2)? Problem Explain 31.<br />
including 3.5 ounces. First-class<br />
x→2<br />
letter rates do not apply to letters<br />
Based on these examples, your you reasoning. might be tempted<br />
weighing more than 3.5 ounces.<br />
65. The graph of f (x) = x − 3 to conclude that finding a limit as x<br />
approaches c is simply a matter of substituting the number is a straight c intoline thewith function. a pointThe punched next<br />
Source: U.S. Postal Service Notice 123 few examples show that substitution<br />
3 − x<br />
out. cannot always be used and other strategies need to<br />
be employed.<br />
(a) Find a function C that models the first-class postage charged, (a) What straight line and what point?<br />
in dollars, for a letter weighing w ounces. Assume The w>0. limit of a rational function can be found using substitution, provided the<br />
(b) Use the graph of f to investigate the one-sided limits of f as<br />
(b) What is the domain of C?<br />
number c being approached is in the domain of the rational function. The next example<br />
x approaches 3.<br />
(c) Graph the function C.<br />
shows a strategy that can be tried when c is not in the domain.<br />
(c) Does the graph suggest that lim f (x) exists? If so, what is it?<br />
(d) Use the graph to investigate lim C(w) and lim C(w). Do<br />
x→3<br />
w→2− w→2 +<br />
66. (a) Use a table to investigate lim(1 + x)<br />
these suggest that lim C(w) exists? EXAMPLE 13 Finding the Limit of a Rational 1/x .<br />
x→0<br />
Function<br />
w→2<br />
(e) Use the graph to investigate lim<br />
x 2 + 5x + 6 (b) Use graphing technology to graph g(x) = (1 + x) 1/x .<br />
.<br />
x 2 − 4 (c) What do (a) and (b) suggest about lim<br />
Kathryn Sidenstricker /Dreamstime.com<br />
C(w).<br />
w→0 + Find lim<br />
(f) Use the graph to investigate lim C(w).<br />
x→−2<br />
(1 + x) 1/x ?<br />
x→0<br />
w→3.5 − Solution Since −2 is not CAS in(d) theFind domain lim(1 of+ the x) 1/x rational . function, substitution cannot be<br />
60. First-Class Mail As of April 2016, the U.S. used. Postal But Service this does not mean that the x→0<br />
limit does not exist! Factoring the numerator and<br />
charged $0.94 postage for first-class large envelope the denominator, weighing up to we find<br />
and including 1 ounce, plus a flat fee of $0.21 for each additional<br />
or partial ounce up to and including 13 ounces. First-class rates do Challenge x 2 + 5x Problems + 6 (x + 2)(x + 3)<br />
=<br />
not apply to large envelopes weighing more than 13 ounces.<br />
x<br />
For Problems 2 − 4 (x + 2)(x − 2)<br />
67–70, investigate each of the following limits.<br />
Source: U.S. Postal Service Notice 123 Since x = −2, and we are interested in the limit<br />
{<br />
as 1 x approaches if x is an integer −2, the factor x + 2<br />
f (x) =<br />
(a) Find a function C that models the first-class canpostage be divided charged, out. Then<br />
0 if x is not an integer<br />
in dollars, for a large envelope weighing w ounces. Assume x 2 + 5x + 6 (x + 2)(x + 3)<br />
w>0.<br />
lim<br />
67. = lim<br />
f (x) 68. lim f (x) 69. lim f (x) 70. lim f (x)<br />
x→−2 x 2 − 4 x→−2 x→2 (x + 2)(x −x→1/2 2) = lim x + 3<br />
x→−2 x − 2 = −2 + 3<br />
↑<br />
↑<br />
x→3<br />
↑ −2 − 2 =−1 x→0 4<br />
(b) What is the domain of C?<br />
Factor<br />
x = −2<br />
Divide out ( x + 2)<br />
Use the Limit of a<br />
Rational Function<br />
NOW WORK Problem 35 and AP® Practice Problem 2.<br />
■<br />
AP® Calc Skill Builder<br />
for Example 11<br />
Finding the Limit of a Rational Function<br />
3<br />
x − 9x<br />
Find lim<br />
→ x − 3 .<br />
x 3<br />
Solution<br />
3<br />
x 9x<br />
x x<br />
lim lim ( 2<br />
−<br />
−<br />
=<br />
9)<br />
x→3<br />
x − 3 x→3<br />
x − 3<br />
x( x− 3)( x + 3)<br />
= lim<br />
x→3<br />
x − 3<br />
= lim x( x+ 3) = 3(3+ 3) = 18<br />
x→3<br />
To reinforce notational fluency, remind<br />
students that the limit notation must be<br />
included in each step of the factorization.<br />
Also, encourage them to proceed gradually,<br />
step by step, when factoring expressions.<br />
For your visual learners, use the graph of<br />
the function to explain this limit.<br />
24<br />
22<br />
y<br />
18<br />
15<br />
12<br />
9<br />
6<br />
3<br />
Alternate Example<br />
Finding the Limit of a Rational Function<br />
x − x<br />
Find lim 9 3/2 7/2<br />
.<br />
→ + 5/2 3/2<br />
x 0 x − 3x<br />
Solution<br />
Factor numerator and denominator:<br />
x − x<br />
lim 9<br />
→0<br />
x − 3x<br />
x<br />
3/2 7/2<br />
=<br />
lim<br />
+ 5/2 3/2 +<br />
x→0<br />
x<br />
x<br />
2<br />
4<br />
x<br />
(9 − x )<br />
( x−<br />
3)<br />
3/2 2<br />
3/2<br />
TRM Section 1.2: Worksheet 2<br />
In this two-page worksheet, graphs are provided<br />
for 6 limit questions that each require some<br />
form of algebraic manipulation. An additional 6<br />
questions cover the properties of limits given a<br />
table of values.<br />
TRM Section 1.2: Worksheet 3<br />
This worksheet contains 8 limit questions that can<br />
be solved using techniques learned in this section.<br />
Graphs are not provided for answer verification.<br />
=<br />
−x<br />
lim<br />
x<br />
+<br />
x→0<br />
( x −9)<br />
( x−<br />
3)<br />
( x− 3)( x+<br />
3)<br />
=−lim +<br />
x→0<br />
( x − 3)<br />
=− lim ( x + 3) =−3<br />
+<br />
x→0<br />
3/2 2<br />
3/2<br />
Section 1.2 • Limits of Functions Using Properties of Limits<br />
97<br />
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