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<strong>Sullivan</strong> AP˙<strong>Sullivan</strong>˙Chapter01 October 8, 2016 17:4<br />
Section 1.3 • Continuity 103<br />
y<br />
c<br />
y f (x)<br />
(c, f (c))<br />
x<br />
y<br />
1.3 Continuity<br />
c<br />
(c, f (c))<br />
OBJECTIVES When you finish this section, you should be able to:<br />
1 Determine whether a function is continuous at a number (p. 103)<br />
2 Determine intervals on which a function is continuous (p. 106)<br />
3 Use properties of continuity (p. 108)<br />
4 Use the Intermediate Value Theorem (p. 110)<br />
Sometimes lim f (x) equals f (c) and sometimes it does not. In fact, f (c) may not even<br />
x→c<br />
be defined and yet lim f (x) may exist. In this section, we investigate the relationship<br />
x→c<br />
between lim f (x) and f (c). Figure 21 shows some possibilities.<br />
x→c<br />
y f (x)<br />
x<br />
y<br />
c<br />
y f (x)<br />
(b) lim f(x) lim f(x) f (c) (c) lim f (x) lim f(x)<br />
(a) lim f(x) lim f(x) f (c)<br />
x→c x→c x→c x→c x→c x→c<br />
f(c) is not defined.<br />
Figure 21<br />
x<br />
y<br />
c<br />
(c, f (c))<br />
y f (x)<br />
(d) lim f (x) lim f (x)<br />
x→c x→c<br />
f (c) is defined.<br />
x<br />
y<br />
c<br />
y f (x)<br />
(e) lim f (x) lim f (x)<br />
x→c x→c<br />
f (c) is not defined.<br />
Of these five graphs, the “nicest” one is Figure 21(a). There, lim<br />
x→c<br />
f (x) exists and is<br />
equal to f (c). Functions that have this property are said to be continuous at the number c.<br />
This agrees with the intuitive notion that a function is continuous if its graph can be drawn<br />
without lifting the pencil. The functions in Figures 21(b)–(e) are not continuous at c, since<br />
each has a break in the graph at c. This leads to the definition of continuity at a number.<br />
DEFINITION Continuity at a Number<br />
A function f is continuous at a number c if the following three conditions are met:<br />
• f (c) is defined (that is, c is in the domain of f )<br />
• lim f (x) exists<br />
x→c<br />
• lim f (x) = f (c)<br />
x→c<br />
If any one of these three conditions is not satisfied, then the function is discontinuous<br />
at c.<br />
NOW WORK AP® Practice Problems 1 and 2.<br />
1 Determine Whether a Function Is Continuous at a Number<br />
EXAMPLE 1<br />
Teaching Tip<br />
Another advantage to the left–right–center<br />
definition of continuity is that it will help students to<br />
identify the type of discontinuity a function exhibits.<br />
If lim fx ( ) ≠ lim fx ( ), then the function jumps<br />
− +<br />
x→c x→c<br />
from one value to another and therefore is<br />
classified as a jump discontinuity.<br />
If lim fx ( ) = lim fx ( ), then the function does not<br />
− +<br />
x→c x→c<br />
jump. That doesn’t mean it is continuous, though.<br />
We still have to determine if the left- and righthand<br />
limits equal fc (). If they do not, there is a tiny<br />
hole. This is called a removable discontinuity.<br />
Determining Whether a Function Is Continuous<br />
at a Number<br />
(a) Determine whether f (x) = 3x 2 − 5x + 4 is continuous at 1.<br />
(b) Determine whether g(x) = x 2 + 9<br />
is continuous at 2.<br />
x 2 − 4<br />
Solution (a) We begin by checking the conditions for continuity. First, 1 is in the<br />
domain of f and f (1) = 2. Second, lim f (x) = lim(3x 2 − 5x + 4) = 2, so lim f (x)<br />
x→1 x→1 x→1<br />
exists. Third, lim f (x) = f (1). Since the three conditions are met, f is continuous at 1.<br />
x→1<br />
(b) Since 2 is not in the domain of g, the function g is discontinuous at 2. ■<br />
x<br />
TRM Alternate Examples<br />
Section 1.3<br />
You can find the Alternate Examples for<br />
this section in PDF format in the Teacher’s<br />
Resource Materials.<br />
TRM AP® Calc Skill Builders<br />
Section 1.3<br />
You can find the AP ® Calc Skill Builders for<br />
this section in PDF format in the Teacher’s<br />
Resource Materials.<br />
Teaching Tip<br />
The definition of continuity can also be<br />
stated this way:<br />
A function is continuous at a number c if<br />
lim fx ( ) = lim fx ( ) = fc ().<br />
− +<br />
x→c x→c<br />
Students may remember this set of 3<br />
checks because they examine the limit<br />
from the left, the limit from the right, and<br />
then the center, the value at c.<br />
The three checks can become three<br />
2<br />
questions. For instance, for lim x<br />
x→3<br />
1. What is the limit of f (x) as x<br />
approaches 3 from the right?<br />
2. What is the limit of f (x) as x<br />
approaches 3 from the left?<br />
3. What is the value of f(x) at x = 3?<br />
Since these three values are 9, then f(x) =<br />
x 2 is continuous at x = 3.<br />
In contrast, consider the following function<br />
at c = 3:<br />
⎛<br />
⎜<br />
fx ( ) = ⎜<br />
⎜<br />
⎝<br />
2<br />
x , x < 3<br />
4, x = 3<br />
x+ 6, x > 3<br />
1. lim x 2 as x approaches 3 from the<br />
left = 9<br />
2. lim x + 6 as x approaches 3 from the<br />
right = 9<br />
3. f (3) = 4<br />
Since these three values are not the same,<br />
then f is not continuous.<br />
Teaching Tip<br />
Remind the students that if<br />
lim fx ( ) = lim fx ( ) then lim fx ( ) exists.<br />
− +<br />
x→c x→c<br />
x→c<br />
If it helps their understanding, consider<br />
using this phrase: If the limit of a function<br />
from the left equals the limit of the<br />
function from the right, then the limit in<br />
general exists.<br />
Section 1.3 • Continuity<br />
103<br />
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