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1.Algebra Booster

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2.22 Algebra <strong>Booster</strong><br />

2. The solutions of<br />

2 2<br />

x - 2x+ 1 x - 2x+<br />

1 4<br />

(2 + 3) + (2 - 3) = are<br />

(2 - 3)<br />

(a) (1 ± 3), 1 (b) (1 ± 2), 1<br />

(c) (1 ± 3), 2 (d) (1 ± 2), 2<br />

3. The number of real solutions of the equation<br />

t<br />

t<br />

(15 + 4 14) + (15 - 4 14) = 30 is, where t = x 2 – 2|x|<br />

(a) 0 (b) 2 (c) 4 (d) 6<br />

4. If a, b are the roots of the equation<br />

1! + 2! + 3! + … + (x – 1)! + x! = k 2 and k Œ I, where<br />

a < b and if a 1<br />

, a 2<br />

, a 3<br />

, a 4<br />

are the roots of the equation<br />

x 2 2 3 4 2<br />

-[1+ 2 a + 3 a + 4 a + 5 a ] x + [-5 b ]<br />

( a + b) + ( a - b) = 2 a,<br />

where a 2 – b = 1 and [] = GIF, the value of<br />

| a1+ a2+ a3+ a4- a1a2a3a4|<br />

is<br />

(a) 216 (b) 221 (c) 224 (d) 209<br />

Passage IV<br />

Consider the cubic equation f(x) = ax 3 + bx 2 + cx + d = 0,<br />

where a, b, c, d are real numbers.<br />

Then<br />

1. If two roots are equal in magnitude but opposite in sign,<br />

then<br />

(a) bc + ad = 0 (b) bc – ad = 0<br />

(c) ab = cd (d) ab + cd = 0.<br />

2. If the equation has one and only one positive real roots,<br />

then<br />

(a) b 2 < 3ac, ad > 0 (b) b 2 > 3ac, ad > 0<br />

(c) b 2 < 3ac, ad < 0 (d) b 2 > 3ac, ad < 0<br />

3. If a = 1 and one root of the given equation is unity, the<br />

value of b + c + d is<br />

(a) 36 (b) 0 (c) –1 (d) 1<br />

Passage V<br />

Let a, b be the roots of x 2 + px + q = 0 and g, d the roots of<br />

x 2 + rx + s = 0.<br />

On the basis of the above information, answer the following<br />

questions.<br />

1. If a, b, g, d are in GP, then<br />

(a) q 2 r 2 = p 2 s 2 (b) q 2 r 2 + p 2 s 2 = 0<br />

(c) qr 2 + ps 2 = 0 (d) qr 2 = ps 2<br />

2. If a, b, g, d are in AP, then<br />

(a) p 2 + r 2 = 4(s + q) (b) p 2 – r 2 = 4(s – q)<br />

(c) p 2 – r 2 = 2(s – q) (d) p 2 + r 2 = 2(s + q)<br />

3. The value of (a – g)(a – d)(b – g )(b – d) is<br />

(a) p 2 s 2 – pr(q + s) + s(p 2 – 2q) + qr 2<br />

(b) q 2 – s 2 – pr(q + s) + s(p 2 –2q) + qr 2<br />

(c) q 2 + s 2 – pr(q + s) + s(p 2 – 2q) + qr 2<br />

(d) q 2 + s 2 – pr(q – s) + s(p 2 – 2q + qr 2 )<br />

Match Matrix<br />

(For JEE-Advanced Examination Only)<br />

1. Observe the following Columns:<br />

Column I<br />

Column II<br />

(A) If the number of solutions<br />

of the sys-<br />

(P) m is the AM of n and p.<br />

tem of equations x<br />

+ 2y = 6 and |x – 3|<br />

= y is m,<br />

(B) If x and y are integers<br />

and (x – 8)<br />

(Q) n is the GM of m and p<br />

(x – 10) = 2 y , and<br />

the number of solutions<br />

be n,<br />

(C) If the number of integral<br />

solutions for<br />

(R) p is the HM of m and n<br />

the equation x + 2y<br />

= 2xy is p,<br />

(S) p m<br />

m + p<br />

n =<br />

mp<br />

(T)<br />

2. Observe the following Columns:<br />

Column I<br />

(A) If a + b + 2c = 0, c π 0, the<br />

equation ax 2 + bx + c = 0 has<br />

(B) If a, b, c ΠR such that 2a +<br />

3b + 6c = 0, the equation ax 2<br />

+ bx + c = 0 has<br />

(C) Let a, b, c be non-zero real<br />

numbers such that<br />

1<br />

8 2<br />

(1+ cos x)( ax + bx+<br />

c) dx<br />

Ú<br />

0<br />

2<br />

Ú<br />

0<br />

8 2<br />

= (1+ cos x)(ax + bx+<br />

c) dx,<br />

the equation ax 2 + bx + c = 0<br />

has<br />

m=<br />

n p n p n.....<br />

Column II<br />

(P) at least one<br />

root in<br />

(–2, 0)<br />

(Q) at least one<br />

root in<br />

(–1, 0)<br />

(R) at least one<br />

root in<br />

(–1, 1)<br />

(S) at least one<br />

root in (0, 1)<br />

(T) at least one<br />

root in (0, 2)<br />

3. Observe the following Columns:<br />

Column I<br />

Column II<br />

(A) If N be the number of solutions<br />

and S be the sum of<br />

all roots of the equation |x<br />

– |4 – x|| –2x = 4,<br />

(P) S = 0

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