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1.Algebra Booster

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5.2 Algebra <strong>Booster</strong><br />

8. RESTRICTED PERMUTATIONS<br />

String Method<br />

(i) Togetherness<br />

The number of permutations of n different things taken all at<br />

a time when m specified things always come together is given<br />

as (n – m + 1)! ¥ m!.<br />

(ii) Non-togetherness<br />

The number of permutations of n different things taken all at a<br />

time when m specified things never come together is given as<br />

n! – (n – m + 1)! ¥ m!.<br />

9. RANK OF A WORD IN DICTIONARY<br />

Rank of a word is the position of that word, when we arrange<br />

them in alphabetic order according to the English dictionary.<br />

To understand the concept of the rank of a word we should<br />

remember the following steps.<br />

Consider the three letters A, B and C.<br />

The number of arrangement of the letters A, B and C is 3!<br />

and their order is<br />

ABC—1st word<br />

ACB—2nd word<br />

BAC—3rd word<br />

BCA—4th word<br />

CAB—5th word<br />

CBA—6th word<br />

If I ask you, what is the rank of the word BCA? The answer<br />

is 4th.<br />

10. GAP METHOD<br />

The number of permutations of n different things taken all at<br />

a time when m specified things, no two of which are to occur<br />

together is n + 1 P m<br />

¥ n!.<br />

11. CIRCULAR PERMUTATIONS<br />

We have discussed earlier so far, the permutations of objects<br />

(for things) in a row. Such types of permutations are called<br />

linear permutations of linear arrangements. If n different<br />

things can be arranged in a row, the linear arrangements is<br />

n!, whereas every linear arrangements have a beginning and<br />

end but in circular permutations, there is neither beginning<br />

nor end.<br />

When clockwise and anti-clockwise orders are taken as<br />

different, the number of circular permutations of n different<br />

things taken all at a time is (n – 1)!<br />

But, when the clockwise and anti-clockwise orders are<br />

not different, i.e. the arrangements of beads in a necklace,<br />

arrangements of flowers in a garland, etc., the number of circular<br />

permutations of n different things = 1 ¥ ( n - 1)! .<br />

2<br />

12. RESTRICTED CIRCULAR PERMUTATIONS<br />

(i) If clockwise and anti-clockwise arrangements are taken<br />

as different, the number of circular permutations of<br />

n different things, taken r at a time is given by<br />

n<br />

P<br />

= r<br />

r<br />

(ii) If clockwise and anti-clockwise arrangements are not<br />

taken as different, the number of circular permutations<br />

of n different things, taken r at a time<br />

n<br />

P<br />

= r<br />

2 r<br />

13. COMBINATIONS<br />

The different groups or selections of a number of things taken<br />

some or all of them at a time are called combinations.<br />

The number of combinations of n different things taken r at<br />

a time is denoted by n n n!<br />

C r<br />

and is defined as Cr<br />

=<br />

,<br />

r! ¥ ( n - r)!<br />

where r £ n, r Œ W, n Œ N.<br />

14. SOME IMPORTANT RESULTS TO REMEMBER<br />

(i) n C r<br />

= nC n – r<br />

(ii) n C x<br />

= n C y<br />

fi x = y or x + y = n<br />

(iii) n C r<br />

+ n C r – 1<br />

= n + 1 C r<br />

n<br />

Cr<br />

n- r + 1<br />

(iv) =<br />

n<br />

C -<br />

r<br />

r<br />

1<br />

n n n-1 n( n-<br />

1) n-2<br />

(v) C = ¥ C = ¥ C<br />

r<br />

r( r - 1)<br />

and so on.<br />

(vi) n C 0<br />

+ n C 1<br />

+ n C 2<br />

+ … + n C n<br />

= 2 n<br />

(vii)<br />

r r-1 r-2<br />

n 2 n 2 n 2 n 2 2n<br />

0 + 1 + 2 + + n =<br />

C C C C C<br />

15. RESTRICTED COMBINATIONS<br />

(i) The number of selections of r objects out of n different<br />

objects when<br />

(a) k particular objects are always included = n – k C r – k<br />

(b) k particular objects are never included = n – k C r<br />

(ii) The number of combinations of r things out of n different<br />

things such that k particular things are not included<br />

in any selection = n C r<br />

– n – k C – k<br />

(iii) The number of selections of r consecutive things out of<br />

n things in a row = n – r +1<br />

(iv) The number of selections of r consecutive things out of<br />

Ïn : r < n<br />

n things along a circle = Ì<br />

Ó1:<br />

r = n<br />

n

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