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1.Algebra Booster

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7.38 Algebra <strong>Booster</strong><br />

1 a a<br />

47 The given determinant = 1 b<br />

2<br />

b<br />

1 c<br />

2<br />

c<br />

2<br />

1 a a<br />

2 2 ÊR2Æ R2 - R1ˆ<br />

= 0 b – a b - a Á<br />

ËR 2 2<br />

3Æ R3-<br />

R ˜<br />

1¯<br />

0 c – a c - a<br />

2 2<br />

b - a b - a<br />

=<br />

2 2<br />

c – a c - a<br />

1 b + a<br />

= ( b - a)( c - a) 1 c + a<br />

= (b – a)(c – a)(c + a – b – a)<br />

= (b – a)(c – a)(c – b)<br />

= (a – b)(b – c)(c – a)<br />

1 a b+<br />

c<br />

48. The given determinant = 1 b c+<br />

a<br />

1 c a+<br />

b<br />

1 a a + b + c<br />

= 1 b b + c + a ( C3Æ C2+<br />

C3)<br />

1 c c + a + b<br />

1 a 1<br />

= ( a + b + c)1 b 1<br />

1 c 1<br />

= (a + b + c) ¥ 0<br />

= 0<br />

49. The given determinant is<br />

sin a cos b cos ( a + q)<br />

sin b cos b cos ( b + q)<br />

sin g cos g cos ( g + q)<br />

sin a cos b 0<br />

= sin b cos b 0<br />

sin g cos g 0<br />

[ C3ÆC3- ( C1cosq<br />

+ C2sin q)]<br />

= 0<br />

50. The given determinant =<br />

2<br />

1 bc a( b + c)<br />

1 ca b( a + c)<br />

1 ab c( a + b)<br />

1 bc bc + ab + ac<br />

= 1 ca ac + ab + bc ( C3Æ C2+<br />

C3)<br />

1 ab ab + ac + bc<br />

1 bc 1<br />

= ( ab + bc + ca) ¥ 1 ca 1<br />

1 ab 1<br />

= (ab + bc + ca) ¥ 0<br />

= 0<br />

51. The given determinant<br />

a + b + 2c a b<br />

= c b + c + 2a b<br />

c a c + a + 2b<br />

2( a + b + c)<br />

a b<br />

= 2( a + b + c) b + c + 2a b<br />

2( a + b + c) a c + a + 2b<br />

(C 1<br />

Æ C 1<br />

+ C 2<br />

+ C 3<br />

)<br />

1 a b<br />

=2( a + b + c) ¥ 1 b + c + 2a b<br />

1 a c + a + 2b<br />

1 a b<br />

=2( a + b + c) ¥ 0 b + c + a 0<br />

0 0 c + a + b<br />

ÊR2Æ R2 - R1ˆ<br />

Á<br />

ËR3Æ R3-<br />

R ˜<br />

1¯<br />

1 a b<br />

3<br />

= 2( a + b + c) ¥ 0 1 0<br />

0 0 1<br />

= 2(a + b + c) 3 ¥ 1<br />

= 2(a + b + c) 3<br />

52. The given determinant<br />

b + c a a<br />

= b c + a b<br />

c c a + b<br />

2( b + c) 2( c + a) 2( a + b)<br />

= b c + a b<br />

c c a + b<br />

( b + c) ( c + a) (R 1<br />

Æ R 1<br />

+ R 2<br />

+ R 3<br />

)<br />

( a + b)<br />

= 2 b c + a b<br />

c c a + b<br />

b + c ( c + a) ( a + b)<br />

= 2 – c 0 – a<br />

– b – a 0<br />

ÊR2Æ R2 - R1ˆ<br />

Á<br />

ËR Æ R - R ˜<br />

¯<br />

3 3 1<br />

0 c b<br />

= 2– c 0 – a ( R1Æ R1+ R2 + R3)<br />

– b – a 0<br />

= 2[–c(–ab – 0) + b(ca – 0)]

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