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Measure, Integration & Real Analysis, 2021a

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124 Chapter 5 Product <strong>Measure</strong>s<br />

The next result will allow us to define the product of two σ-finite measures.<br />

5.20 measure of cross section is a measurable function<br />

Suppose (X, S, μ) and (Y, T , ν) are σ-finite measure spaces. If E ∈S⊗T,<br />

then<br />

(a) x ↦→ ν([E] x ) is an S-measurable function on X;<br />

(b) y ↦→ μ([E] y ) is a T -measurable function on Y.<br />

Proof We will prove (a). If E ∈S⊗T, then [E] x ∈T for every x ∈ X (by 5.6);<br />

thus the function x ↦→ ν([E] x ) is well defined on X.<br />

We first consider the case where ν is a finite measure. Let<br />

M = {E ∈S⊗T : x ↦→ ν([E] x ) is an S-measurable function on X}.<br />

We need to prove that M = S⊗T.<br />

If A ∈Sand B ∈T, then ν([A × B] x )=ν(B)χ A<br />

(x) for every x ∈ X (by<br />

Example 5.5). Thus the function x ↦→ ν([A × B] x ) equals the function ν(B)χ A<br />

(as<br />

a function on X), which is an S-measurable function on X. Hence M contains all<br />

the measurable rectangles in S⊗T.<br />

Let A denote the set of finite unions of measurable rectangles in S⊗T. Suppose<br />

E ∈A. Then by 5.13(b), E is a union of disjoint measurable rectangles E 1 ,...,E n .<br />

Thus<br />

ν([E] x )=ν([E 1 ∪···∪E n ] x )<br />

= ν([E 1 ] x ∪···∪[E n ] x )<br />

= ν([E 1 ] x )+···+ ν([E n ] x ),<br />

where the last equality holds because ν is a measure and [E 1 ] x ,...,[E n ] x are disjoint.<br />

The equation above, when combined with the conclusion of the previous paragraph,<br />

shows that x ↦→ ν([E] x ) is a finite sum of S-measurable functions and thus is an<br />

S-measurable function. Hence E ∈M. We have now shown that A⊂M.<br />

Our next goal is to show that M is a monotone class on X × Y. To do this, first<br />

suppose E 1 ⊂ E 2 ⊂··· is an increasing sequence of sets in M. Then<br />

(<br />

ν [<br />

∞⋃<br />

k=1<br />

) ( ⋃ ∞<br />

E k ] x = ν<br />

k=1<br />

)<br />

([E k ] x )<br />

= lim<br />

k→∞<br />

ν([E k ] x ),<br />

where we have used 2.59. Because the pointwise limit of S-measurable functions<br />

is S-measurable (by 2.48), the equation above shows that x ↦→ ν ( [ ⋃ ∞<br />

k=1<br />

E k ] x<br />

)<br />

is<br />

an S-measurable function. Hence ⋃ ∞<br />

k=1<br />

E k ∈M. We have now shown that M is<br />

closed under countable increasing unions.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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